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WITCHER [35]
3 years ago
7

Writer and solve a real-word promblem involving the multiplication of a fraction and a whole number whose is between 10and15

Mathematics
1 answer:
pickupchik [31]3 years ago
8 0
Give me an operation like the one you are talki ng about and I can solve it
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Dang...H0: μ = 115 HA: μ ≠ 115 Sample mean = 120 Standard deviation = 25 Standard error of mean = σ / √ n Standard error of mean = 25 / √ 100 SE = 25/10 Standard error of mean 2.5 z = (xbar- μ ) / SE z = (120-115) / 2.5 z = 2 p-value = 2 P( z > 2) = 2(0.0228) = 0.0456 the data are statistically significant at level = .05, but not at level = .01. 2) H0: μ = 115 HA: μ ≠ 115 Sample mean = 119 Standard deviation = 25 Standard error of mean = σ / √ n Standard error of mean = 25 / √ 100 SE = 25/10 Standard error of mean 2.5 z = (xbar- μ ) / SE z = (119-115) / 2.5 z = 1.6 p-value = 2P( z > 1.6) = 2(0.0548) =0.1096 3) a statement about the population the researcher suspects is true, and is trying to find evidence for. 4) Sample mean = 80 Standard deviation = 20 Standard error of mean = σ / √ n Standard error of mean = 20 / √ 100 SE = 20/10 The Standard error of mean 2 Confidence interval 80-(2)(1.645) and 80+(2)(1.645) (76.7, 83.3)
4 0
4 years ago
The area of a rectangle in 24 units. A diagonal drawn from one corner to another divides the rectangle into two right triangles.
nlexa [21]

Answer:

12 sq u

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

Well, assuming the shaded triangle is one of those two triangles, its area would be 12 sq u.

Why? Because its length would be the same as the retances, as would its height, and to find the area of a triangle, you'd do L*H/2 which would be 24/2=12 sq u

(っ◔◡◔)っ ♥ Hope this helped, have a great day! ♥

˜”*°•.˜”*°• ~Star •°*”˜.•°*”˜

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3 years ago
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4 years ago
Is f = 2 a solution to the inequality below?
lana66690 [7]

Answer: no

Step-by-step explanation: 2 is not less than 1

3 0
3 years ago
Read 2 more answers
Just number 3 is fine please but if you could also 4​
PIT_PIT [208]

Answer:

3. r = -8

4. x = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

2(-5r + 2) = 84

<u>Step 2: Solve for </u><em><u>r</u></em>

  1. Divide 2 on both sides:                    -5r + 2 = 42
  2. Subtract 2 on both sides:                 -5r = 40
  3. Divide -5 on both sides:                    r = -8

<u>Step 3: Check</u>

<em>Plug in r into the original equation to verify it's a solution.</em>

  1. Substitute in <em>r</em>:                   2(-5(-8) + 2) = 84
  2. Multiply:                             2(40 + 2) = 84
  3. Add:                                   2(42) = 84
  4. Multiply:                             84 = 84

Here we see that 84 does indeed equal 84.

∴ r = -8 is a solution of the equation.

<u>Step 4: Define equation</u>

264 = -8(-8 + 5x)

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Divide both sides by -8:                    -33 = -8 + 5x
  2. Add 8 to both sides:                          -25 = 5x
  3. Divide 5 on both sides:                      -5 = x
  4. Rewrite:                                               x = -5

<u>Step 6: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in<em> x</em>:                    264 = -8(-8 + 5(-5))
  2. Multiply:                               264 = -8(-8 - 25)
  3. Subtract:                              264 = -8(-33)
  4. Multiply:                               264 = 264

Here we see that 264 does indeed equal 264.

∴ x = -5 is a solution of the equation.

8 0
3 years ago
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