Answer: c for the first part
1,6 for the second
nether for the third
Step-by-step explanation:
all on edg

Rounding to nearest thousand gives 76,000 mg of chlorine
Answer:
Option (2)
Step-by-step explanation:
Given:
AC is an angle bisector of ∠DAB and ∠DAB
m∠BCA ≅ m∠DCA
m∠BAC ≅ m∠DAC
To Prove:
ΔABC ≅ ΔADC
Solution:
Statements Reasons
1). m∠BCA ≅ m∠DCA 1). Given
2). m∠BAC ≅ m∠DAC 2). Given
3). AC ≅ AC 3). Reflexive property
4). ΔABC ≅ ΔADC 4). ASA property of congruence
Therefore, Option (2) will be the correct option.
Let`s assume that points M, N and P are the touching points of those 3 circles:Then:Y M + M Z = 14,Z N + N X = 20X P + P Y = 18And also: M Z = ZN, Y M = P Y and N X = X P.Now we have a system of 3 equations ( Y M, M Z and X P are the radii of each circle ):Y M + M Z = 14M Z + X P = 20X P + Y M = 18 Y M - M Z = - 14+X P + Y M = 18 X P - M Z = 4Y M - M Z = - 14+M Z + X P = 20 X P - Y M = 6 /* ( - 1 )X P - M Z = 4 X P + Y M = - 6 X P - M Z = 4 Y M - M Z = - 2 Y M + M Z = 14 2 Y M = 12 => Y M = 6M Z - 6 = 2 => M Z = 8X P + 6 = 18
X P = 12
Radii of the circles are: 12, 8 and 6.