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Mice21 [21]
3 years ago
15

Why isn't it possible to divide a factor with 0? And if so, what is the answer? 0? ∞?

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0

let's think about it, let's divide say hmmm 15 by 0, in a fraction

\bf \cfrac{\textit{part of a pie}}{\textit{whole pie}}\qquad \cfrac{15}{0}\implies \cfrac{\textit{taking 15 pieces}}{\textit{from a whole pie that's 0, or not there}}

now, how can you take any pieces of a pie that's non-existent? I mean that requires magic!!.

now, let's do it using a simple long division, 15 ÷ 0, so 0 is the divisor, anything times 0 is 0, what is our first digit in the quotient to get 15? 0 * 15 = 0, 0 * 1,000,000 = 0, there isn't any number we can possible use to get a quotient.

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State the domain and range of the function f(x) = 2 [[x]]
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Tennis balls: Must rebound approximately 111 cm when dropped from 200 cm. Soccer balls: Must rebound approximately 120 cm when d
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Answer:

There is no basis for comparison because the effect of the other variables that are not being studied are not minimized

Step-by-step explanation:

The rate at which each type of ball bounce are;

Tennis balls;

The height to which the ball is must rebounds ≈ 111 cm

The height from which the ball is dropped = 200 cm

Surface = Steel plate

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The height to which the ball must rebounds ≈ 5.35 inches

The height from which the ball is dropped = 72 inches

Surface = Wooden floor

Squash balls

The height to which the ball must rebounds ≈ 29.5 inches

The height from which the ball is dropped = 100 inches

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Therefore, given that the experimental are performed with different variables of height from which each type of ball is dropped, the surface to which the ball is dropped, the angle of the surface to which the ball is dropped, there is no controlled variable to provide a basis for comparison

5 0
3 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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3 years ago
A surveyor measures the top of a lighthouse 70ft away from him (see picture). his angle-measuring device is 4 ft above the groun
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Step-by-step explanation:

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