Answer:

Step-by-step explanation:
We're going to have to work backwards.
The sum of 4 and k is
.
Half is simply that divided by 2.

Now, we'll subtract 8 from it.

Bam!
Answer:
$630.50
Step-by-step explanation:
10(y+2)-y=2(9y-8)
Mutiply the first bracket by 10
Mutiply the second bracket by 2
(10)(y)(10)(2)= 10y+20
(2)(9y)(2)(-8)= 18y-16
10y+20-y= 18y-16
10y-y+20= 18y-16
9y+20= 18y-16
move 18y to the other side
sign changes from +18y to -18y
9y-18y+20= 18y-18y-16
-9y+20= -16
move +20 to the other side
sign changes from +20 to -20
-9y+20-20=-16-20
-9y= -36
divide by -9
-9y/-9= -36/-9
y= 4
Answer: y= 4
Answer:
-5/6, -2/5, 2/5, 5/6
Step-by-step explanation:
put the fractions in your calculator and then click the fraction to decimal button and press enter.
Answer:
The minimum sample size needed for use of the normal approximation is 50.
Step-by-step explanation:
Suitability of the normal distribution:
In a binomial distribution with parameters n and p, the normal approximation is suitable is:
np >= 5
n(1-p) >= 5
In this question, we have that:
p = 0.9
Since p > 0.5, it means that np > n(1-p). So we have that:





The minimum sample size needed for use of the normal approximation is 50.