Help me please,Thanks

a fruit salad is made from pineapples, pears, and peaches mixed in the ratio of 2 to 3 to 5, respectively, by weight. what fract

musickatia [10]

2/10 or 1/5, which is 20%

6 0

4 years ago

What's the area of this shape

spin [16.1K]

Answer:

L x W x H

Step-by-step explanation:

if my calculations are correct the length is 2 the width is 3 and the height is 3

Therefore the answer is (2 x 3) = 6 x3

So the answer is 18.

Hope it helps, if it is incorrect than i am extremely sorry, wish you the best of luck and have a great day/midday/evening. BYYEEEEEEE

5 0

3 years ago

tapes-r-us is have a sale on hq tape players. The regular price is $60. The discount is $18. What percent discount is this?

olga nikolaevna [1]

The discount is 30%

Step-by-step explanation:

Given

Price of tape = $60

Discount = $18

In order to find the percentage, we will use the percentage formula

$Percentage = \frac{discount}{Price}*100\\= \frac{18}{60} *100\\=0.3 * 100\\= 30\%$

Hence,

The discount is 30%

Keywords: Percent, sale

Learn more about percentage at:

#LearnwithBrainly

7 0

3 years ago

15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.

Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = $30C5 = \frac{30 !}{(30-5)!5!} \\$

$30C5 = 142506$ ways

Number of ways of selecting 5 good bulbs from 26 bulbs = $26C5 = \frac{26 !}{(26-5)!5!} \\$

$26C5 = 65780$ ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = $\frac{26C4 * 4C1}{30C5}$

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) = $\frac{26C3 * 4C2}{30C5}$

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) + Pr(2 defective) + Pr(3 defective) + Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) = $\frac{26C2 * 4C3}{30C5}$

Pr(3 defective) = 0.009

Pr(4 defective) = $\frac{26C1 * 4C4}{30C5}$

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0

3 years ago

I need help on my homework

soldi70 [24.7K]

Answer:

$\displaystyle m\angle AED=32.5^\circ$

Step-by-step explanation:

<u>Angles in a Circle</u>

An exterior angle of a circle is an angle whose vertex is outside a circle and the sides of the angle are secants or tangents of the circle.

Segments AE and DE are secants of the given circle. They form an exterior angle called AED.

The measure of an exterior angle is equal to half the difference of the measure of their intercepted arcs.

Intercepted arcs in the given circle are AD=113° and BC=48°. The exterior angle is:

$\displaystyle m\angle AED=\frac{AD-BC}{2}$

$\displaystyle m\angle AED=\frac{113^\circ-48^\circ}{2}=\frac{65^\circ}{2}$

$\displaystyle m\angle AED=32.5^\circ$

8 0

3 years ago