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3 years ago

Please please help me with this

Mathematics

1 answer:

MrMuchimi3 years ago

3 0

Answer:

y = 9x - 11

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 3, - 38) and (x₂, y₂ ) = (8, 61)

m = $\frac{61+38}{8+3}$ = $\frac{99}{11}$ = 9, thus

y = 9x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (8, 61), then

61 = 72 + c ⇒ c = 61 - 72 = - 11

y = 9x - 11 ← equation of lie

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Answer:

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Step-by-step explanation:

The function value increases by a factor of 40/10 = 4 when x increases by 2. The function can be written as ...

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You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob

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Answer:

a) No

b) 42%

c) 8%

d) X 0 1 2

P(X) 42% 50% 8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c) P(win first game) = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game) × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X 0 1 2

P(X) 42% 50% 8%

P(X = 0) = P(lose both games) = P(lose first game) × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game) × P(win second game)] + [ P(win first game) × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value $\mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66$