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mart [117]
4 years ago
14

What is the slope intercept form of 9x - y = 9

Mathematics
2 answers:
vesna_86 [32]4 years ago
8 0
Slope intercept form= y=mx+b.
y=9x-9



Andre45 [30]4 years ago
4 0
The answer is the letter b.
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A casino claims that its electronic "video roulette" machine is truly random. What should that claim mean?
viva [34]
This should mean that the machine will have a chance of choosing every number likely
4 0
4 years ago
How do I solve 34-5x+2(x-2)=15
LenKa [72]
34-5x+2(x-2)=15      1st get rid of () by distributing the 2.
34-5x+2x-4=15         Now collect like terms.
30-3x=15                  Get -3x by itself by subtracting 30 in both sides.
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8 0
3 years ago
PLEASE HELP, SOLVE THIS PROBLEM AND GIVE ME THE ANSWER!!!
Elenna [48]

Answer:

11 is the answer

Step-by-step explanation: i hope so cuz my calculations gives this answer

5 0
3 years ago
Please help!
larisa [96]
Answer: 
Choice A
1/17; no, they are dependent events

============================================

Explanation:

There are 13 spades and 52 cards total. So 13/52 = 1/4 is the probability of drawing one spade

If we do not replace the card we pull out, then the probability of another spade is 12/51 since there are 12 spades left out of 51 total. 

Multiply the fractions 1/4 and 12/51 to get
(1/4)*(12/51) = (1*12)/(4*51) = 12/204 = 1/17

The two events are not independent because the second event (pulling out a second spade) depends entirely on what happens in the first event (pulling out a first spade). The fact that the probability is altered indicates we have dependent events.

6 0
3 years ago
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

6 0
3 years ago
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