Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀
Now we need to find force on electron
Now for Work done on the electron
The term Milankovitch cycles most closely relate to periodic
changes in Earth’s orbit and angle of tilt relative to sun. So for this
question, the correct option is option “c”. Milankovitch affects actually deals
with the effect of the changes in the earth’s movements with the change in the
climatic conditions. Milankovitch was a Serbian geophysicist and also a great
astronomer. His studies actually helped in relating the climatic changes with
the changes in the tilt of the earth. He was the first person to mathematically
prove this situation.
To solve this problem we will apply the given concept for torque which explains the relationship between the force applied and the distance to a given point. Mathematically this relationship is given as
Where,
Torque
F = Force
d = Distance
Our values are given as,
Therefore replacing we have that the force is
F = 12.72N
Therefore the least amount of force that you must exert is 12.72N
We know from that other question that her mass is 60 kg, and
Weight = (mass) x (gravity)
Earth weight = (60 kg) x (9.8 m/s^2)
Weight = 588 Newtons
