We know that whoever she is is traveling to Antarctica or elsewhere 
in the south polar region.  June is the beginning of Winter there, with 
zero to extremely short daylight.
But we still don't know her name.
        
             
        
        
        
The velocity of  pluck 1 is 12 m/s west.
<h3>What is the conservation of momentum?</h3>
The principle of the conservation of the linear momentum states that momentum before collision is equal to momentum after collision.
Now given that;
m1u1 + m2u2 = m1v1 + m2v2
(0.1 * 15) - (0.1 * 12) = 0.1* v + (0.1 * 15)
1.5 - 1.2 = 0.1v + 1.5
0.3 - 1.5 = 0.1v 
v = -1.2/0.1
v = - 12 m/s
Hence, the velocity of  pluck 1 is 12 m/s west.
Learn  more about linear momentum:brainly.com/question/27988315
#SPJ1
 
        
             
        
        
        
The distance you free-fall from rest is  D = (1/2) (g) (T²) <== memorize this
Height of the platform = (1/2) (9.8 m/s²) (2.4 sec)²
Height = (4.9 m/s²) (5.76 s²)
Height = (4.9/5.76) meters
Height = 28.2 meters (a VERY high platform ... about 93 ft off the water !)
Without air-resistance, your horizontal speed doesn't change.  It's constant.  Traveling 3.1 m/s for 2.4 sec, you cover (3.1 m/s x 2/4 s) = 7.4 m horizontally.
 
        
             
        
        
        

- Speed of the mobile = 250 m/s
- It starts decelerating at a rate of 3 m/s²
- Time travelled = 45s

- Velocity of mobile after 45 seconds

We can solve the above question using the three equations of motion which are:-
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.

We are provided with,
- u = 250 m/s
- a = -3 m/s²
- t = 45 s
By using 1st equation of motion,
⇛ v = u + at
⇛ v = 250 + (-3)45
⇛ v = 250 - 135 m/s
⇛ v = 115 m/s
✤ <u>Final</u><u> </u><u>velocity</u><u> </u><u>of</u><u> </u><u>mobile</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u> </u><u>m</u><u>/</u><u>s</u>
<u>━━━━━━━━━━━━━━━━━━━━</u>
 
        
             
        
        
        
Answer:
The magnitude of the electric field be 171.76 N/C so that the electron misses the plate.
Explanation:
As data is incomplete here, so by seeing the complete question from the search the data is 
vx_0=1.1 x 10^6
ax=0 As acceleration is zero in the horizontal axis so
Equation of motion in horizontal direction is given as 


Now for the vertical distance
vy_o=0
than the equation of motion becomes

Now using this acceleration the value of electric field is calculated as 

Here a is calculated above, m is the mass of electron while q is the charge of electron, substituting values in the equation

So the magnitude of the electric field be 171.76 N/C so that the electron misses the plate.