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kirza4 [7]
3 years ago
8

When a beam of light is incident on a surface, it delivers energy to the surface. The intensity of the beam is defined as the en

ergy delivered per unit area per unit time.
What is the unit of intensity, expressed in SI base units?​
Physics
1 answer:
scoundrel [369]3 years ago
6 0

Answer:

Kg

Explanation:

Given that the definition of intensity is:

The intensity of the beam is defined as the energy delivered per unit area per unit time. That is,

I =( E × t)/A

Which can expressed as

I = J/m^2/s

The S.I Units of

Energy is Joule = kgm^2s^-1

Area A = m^2

Time t = s

Intensity I = kgm^2s^-1 × m^-2 × s

Intensity I = kg

The cubic metres and seconds are cancelled out

Therefore, the S.I units of intensity is kg

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What are subtomic particles<br>​
slavikrds [6]

Answer:

In the physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles. Particle physics and nuclear physics study these particles and how they interact.

Explanation:

3 0
2 years ago
Read 2 more answers
A ball is dropped from a cliff. determine how far the ball fell after 7.5 seconds
grin007 [14]

Answer:

The ball fell 275.625 meters after 7.5 seconds

Explanation:

<u>Free fall </u>

If an object is left on free air (no friction), it describes an accelerated motion in the vertical direction, powered exclusively by the acceleration of gravity. The formulas needed to compute the different magnitudes involved are

V_f=gt

\displaystyle y=\frac{gt^2}{2}

Where V_f is the final speed of the object in free fall, assumed positive downwards, t is the time elapsed since the release and y is the vertical distance traveled by the object

The ball was dropped from a cliff. We need to calculate the vertical distance the ball went down in t=7.5 seconds. We'll use the formula

\displaystyle y=\frac{gt^2}{2}

\displaystyle y=\frac{(9.8)(7.5)^2}{2}

Y=275.625\ m

5 0
3 years ago
Calculate the change in entropy as 0.3071 kg of ice at 273.15 K melts. (The latent heat of fusion of water is 333000 J / kg)
Ostrovityanka [42]

Answer:

374.39 J/K

Explanation:

Entropy: This can be defined as the degree of disorder or randomness of a substance.

The S.I unit of entropy is J/K

ΔS = ΔH/T ..................................... Equation 1

Where ΔS = entropy change, ΔH = Heat change, T = temperature.

ΔH = cm................................... Equation 2

Where,

c = specific latent heat of fusion of water = 333000 J/kg, m = mass of ice = 0.3071 kg.

Substitute into equation 2

ΔH = 333000×0.3071

ΔH = 102264.3 J.

Also, T = 273.15 K

Substitute into equation 1

ΔS = 102264.3/273.15

ΔS = 374.39 J/K

Thus, The change in entropy = 374.39 J/K

3 0
3 years ago
A ______ is something that can be placed between the sun and the subject to diffuse the light. *
Gekata [30.6K]

Answer:

scrim

Explanation:

A scrim is something that can be placed between the sun and the subject to diffuse the light.

An instance of a diffuser is a softbox that is put on its front side around a strobe containing diffusion content. The sun is a form of hard light that is often diffused through a scrim. The light rays are dispersed by putting a scrim between the sun and the object, and the harsh sun's rays is gentler.

6 0
3 years ago
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An elastic conducting material is stretched into a circular loop of 9.65 cm radius. It is placed with its plane perpendicular to
Nadya [2.5K]

Answer:

The induced emf in the coil is 0.522 volts.                        

Explanation:

Given that,

Radius of the circular loop, r = 9.65 cm

It is placed with its plane perpendicular to a uniform 1.14 T magnetic field.

The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , \dfrac{dr}{dt}=-0.756\ m/s

Due to the shrinking of radius of the loop, an emf induced in it. It is given by :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V

So, the induced emf in the coil is 0.522 volts.                                

8 0
3 years ago
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