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Montano1993 [528]
2 years ago
5

Compare and contrast how sound waves behave when they

Physics
1 answer:
Ghella [55]2 years ago
6 0

Answer:

As sound waves move (or more accurately, when they travel by transferring their energy) they interact with physical objects. Soft surfaces will absorb sound while hard surfaces will reflect it. .Hard surfaces reflect sound and soft surfaces absorb sound.

The convex mirror has a reflecting surface that curves outward, resembling a portion of the exterior of a sphere. Light rays parallel to the optical axis are reflected from the surface in a direction that diverges from the focal point, which is behind the mirror

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What are the forces like in a collision?
Anuta_ua [19.1K]

Answer:

The forces are a convergent

Explanation:

6 0
3 years ago
Which vector is the sum of vectors a and b
jeka57 [31]

Answer:

C

Explanation:

Vector A points up

Vector B points right

The combination must be both up and right which is C

5 0
3 years ago
An aluminum clock pendulum having a period of 1.00 s keeps perfect time at 20.0°C.
amm1812

Answer:

a) T ’= 0.999 s ,  b)  t = 3596.4 s

Explanation:

The angular velocity of a simple pendulum is

        w = √g / L

The angular velocity, frequency and period are related

        w = 2π f = 2π / T

        2π / T = √ g / L

        T = 2π √ L / g

        L = T² g / 4π²

        L = 1² 9.8 / 4π²

        L = 0.248 m

To know the effect of the temperature change let's use the thermal expansion ratios

       ΔL = α L ΔT

       ΔL = 24 10⁻⁶ 0.248 (-4 - 20)

       ΔL = 142.8 10⁻⁶ m

       Lf - L = -142. 8 10⁻⁶

       Lf = 142.8 10⁻⁶ + 0.248

       Lf = 0.2479 m

Let's calculate new period

      T ’= 2π √ L / g

      T ’= 2π √ (0.2479 / 9.8)

      T ’= 0.999 s

We can see that the value of the period is reduced so that the clock is delayed

b) change of time in 1 hour

When the clock is at 20 ° C in one hour it performs 3600 oscillations, for the new period the time of this number of oscillations is

       t = 3600 0.999

       t = 3596.4 s

Therefore the clock is delayed almost 4 s

6 0
3 years ago
Considering how the predictions compare to the observations, what does this imply about the mass distributed in the galaxy?
Dafna1 [17]

Answer:

The observations show a higher velocity than is predicted, mainly in the galaxy's outer regions, indicating that there is more mass in the exterior areas than we can see.

8 0
2 years ago
An air-filled parallel-plate capacitor has plates of area 2.30 cm2 2 separated by 1.50 mm. The capacitor is connected to a 12.0-
Gnoma [55]

Answer:

1.357\times 10^{-12}

Explanation:

Relevant Data provided

Area which indicates A = 2.3 cm^2 = 2.3 x 10^-4 m^2

Distance which indicates d = 1.50 x 10^-3 m

Voltage which indicates V = 12 V

According to the requirement, the computation of value of its capacitance is shown below:-

Capacitance, C =  \frac{\epsilon oA}{D}

= \frac{= 8.854\times 10^{-12}\times 2.3\times 10^{-4}}{(1.5 \times 10^{-3})}

= 1.357\times 10^{-12}

Therefore for computing the capacitance we simply applied the above formula.

4 0
3 years ago
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