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barxatty [35]
2 years ago
6

Jumping rope can burn 600 calories per hour. Write and solve an inequality to find the number of hours jumping rope that it woul

d take for you to burn at least 450 calories.
Show work please :)
Mathematics
1 answer:
Simora [160]2 years ago
5 0
X is the number of hours to burn 450 calories:
<em>equality method:</em>
600 calories * 1 hour  = 450 calories * x hours
x hours = 450/600 calories * 1 hour 
x = 0.75 
So, she needs 0.75 hours (45 minutes) to burn 450 calories
<em>
Inequality method:
</em>600x > 450
x > 450/600
x > 0.75
So, she needs at least 0.75 (45 minutes) to burn at least 450 calories.

Hope this Helps! :D
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2 years ago
Solve x(−2) 2 =4(−2)
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X x (-2) x 2 = 4 x (-2)
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3 years ago
Find all the real square roots of 0.0064
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Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12. The next week, Sarah bought 2 loaves o
sergejj [24]

Answer:

Here, b represents one loaf of bread and m represents the one gallon of milk.

As per the statement:

Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12.

⇒4b+m = 12  

It is also given that the next week, Sarah bought 2 loaves of bread and 3 gallons of milk for $13.50.

⇒2b+3m = 13.50

Then; system of equation :

4b+m = 12                   .....[1]

2b+3m = 13.50           .....[2]

Solve for b and m using above system of equations.

Multiply equation [2] by 2 we get;

4b+6m = 27              .....[3]

Subtract equation [1] from [3] we get;

4b+6m - 4b -m= 27-12

Combine like terms;

5m= 15

Divide both sides by 5 we get;

m = $3

Substitute the value of m in equation [1] we get;

4b+3 = 12

Subtract 3 from both sides we get;

4b=9

Divide both sides by 4 we get;

b = $2.25

Therefore, cost of one loaf of bread (b) and one gallon of milk (m) are:

$2.25 ad $3



3 0
3 years ago
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