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mart [117]
3 years ago
12

You can buy a box of 150 sharpie pens for $165 or a dozen for $13.50

Mathematics
1 answer:
Setler [38]3 years ago
5 0

Answer: do the a dozen for $13.50

Step-by-step explanation: It will help save money

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Solve using substitution.<br><br> -5x + 10y = -10<br> y = -2
kykrilka [37]

Answer:

Point Form:

( − 2 , − 2 )

Equation Form:

x =  − 2 ,  y =  − 2

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

8 0
3 years ago
What is equivalent to 3 radical 8
klemol [59]

Answer:

Equivalent 3\sqrt{8}=6\sqrt{2}

Step-by-step explanation:

Given: 3 radical 8

Mathematically 3 radical 8 can be written as 3\sqrt{8}

We have to find an equivalent to 3\sqrt{8}.

Given expression can be written as ,

3\sqrt{8}=3\sqrt{4 \times 2}

On further simplification, we get,

3\sqrt{4 \times 2}=3(\sqrt{4} \sqrt{2} )

We know \sqrt{4}=2

further simplification gives,

3\sqrt{8}=6\sqrt{2}

Thus, Equivalent 3\sqrt{8}=6\sqrt{2}


7 0
3 years ago
What is the value of the expression 10 − ( fraction 1 over 2 )4 ⋅ 48? (1 point)
OlgaM077 [116]

Answer:

Just want to ask if it is 10 - 1/2 × 4 × 48 right? If the expression is this then the answer is -86.

Hope this helps, thank :) !!

6 0
3 years ago
Given f'(x) = (1 − x)(4 − x), determine the intervals on which f(x) is increasing or decreasing.
Sophie [7]
The critical points are at x = 1 and x = 4 giving you the intervals (-inf, 1), (1, 4) and (4, inf).

By substituting x values in these 3 intervals, you can see that f'(x) is positive in the first and third intervals and negative in the second interval.

This means that f(x) is increasing in the first and third intervals and decreasing in the second interval.

The answer is D.
8 0
3 years ago
Read 2 more answers
2w+w^3-1/2w^2 for w=2
mars1129 [50]

The required value is 8

How can we find value?

We will find the value by putting the value of w in the given function to get the required value.

We can find the value of given function foe w=2 as shown below:

Given, function is 2w+w^3-1/2w^2

Let A=2w+w^3-1/2w^2

for w=2

A=2(2)+(2)^3-1/2(2)^2

= 2+8-1/2(4)

=2+8-2

=8

Hence, the required value is 8.

Learn more about function here:

brainly.com/question/875118

#SPJ1

8 0
1 year ago
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