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Rom4ik [11]
2 years ago
7

Solve the inequality and graph its solution: 5n – 10 > 25

Mathematics
2 answers:
solniwko [45]2 years ago
8 0
N is 3. you subtract the 10 from the 25, then divide it by 5.
kozerog [31]2 years ago
5 0
5n  > 35 (Addition property of equality)
n > 7 (division property of equality)
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Please help!!!!!WILL MARK BRAINLIEST.<br>what is the lateral area of the cone​?
Ratling [72]

Answer:

Therefore Lateral Area of Cone is 189.97 yd².

Step-by-step explanation:

Given:

Slant height = 12.1 yd

Diameter = 10 yd

∴ Radius = half of Diameter = 10 ÷ 2 = 5 yd

To Find:

Lateral Area of Cone = ?

Solution:

We know that,

\textrm{Lateral Area of Cone} = \pi\times Radius\times \textrm{Slant height}

Substituting the given values we get

\textrm{Lateral Area of Cone}=3.14\times 5\times 12.1\\\\\textrm{Lateral Area of Cone}=189.97\ yd^{2}

Therefore Lateral Area of Cone is 189.97 yd².

4 0
2 years ago
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sergeinik [125]

That would be Nets 1, 4 and 5.

6 0
3 years ago
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WHOEVER ANSWERS THIS CORRECTLY IN 3 MINS GETS BRAINLIEST!!
tiny-mole [99]

Answer:

Step-by-step explanation:

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2 years ago
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Could you please help me with this problem.
vlabodo [156]

<em>Answer:</em>

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3 years ago
Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''
Nonamiya [84]

Answer:

a-e^x,e^{-x}

b-x^{-2}

c-x^3

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

D^2-1=0

(D-1)(D+1)=0

D=1,-1

Then , the solution of given differential equation

y=e^x,y=e^{-x}

2.7x^2y''+14xy'-14 y=0

Y=y=x^3

y=3x^2

y''=6x

Substitute in the given differential equation

42x^3+42x^3-14x^3\neq 0

Hence, x^3 is not a solution of given differential equation

e^x,e^{-x} are also not a solution of given differential equation.

y=x^{-2}

y'=-2x^{-3}

y''=6x^{-4}

Substitute the values in the differential equation

7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}

=42x^{-2}-28x^{-2}-14x^{-2}=0

Hence, x^{-2} is a solution of given differential equation.

c.7x^2y''-42y=0

y=x^3

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y''=6x

Substitute the values in the differential equation

42x^3-42x^3=0

Hence, x^3 is a solution of given differential equation.

a-e^x,e^{-x}

b-x^{-2}

c-x^3

6 0
3 years ago
Read 2 more answers
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