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gladu [14]
2 years ago
5

Identifying Relationships between Lines

Mathematics
2 answers:
denis-greek [22]2 years ago
6 0

Answer:

1, 3, 5

Step-by-step explanation:

Misha Larkins [42]2 years ago
6 0

Answer:

A,C,E

Step-by-step explanation:

Line A B and Line C G are parallel.

Line C G and Line R S are perpendicular.

Line segment C G  lies in plane X.

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1 of 5
Allisa [31]

Answer:

7/1296

Step-by-step explanation:

Multiply the two probabilities.

7/36 x 1/36 = 7/1296

3 0
3 years ago
Read 2 more answers
Write 9,167.364 in expanded form
beks73 [17]

Answer:

4 + 60 + 300 + NaN + 70000 + 600000 + 1000000 + NaN + 900000000

7 0
2 years ago
DESCRIBE HOW TO WRITE 3 DIGIT NUMBERS IN THREE DIFFERENT WAYS
victus00 [196]
Just put each number in different positions.
425
542
254
All of these numbers are different and use the same 3 digits
3 0
3 years ago
The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep
Alchen [17]
Ooh, fun

geometric sequences can be represented as
a_n=a(r)^{n-1}
so the first 3 terms are
a_1=a
a_2=a(r)
a_2=a(r)^2

the sum is -7/10
\frac{-7}{10}=a+ar+ar^2
and their product is -1/125
\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3

from the 2nd equation we can take the cube root of both sides to get
\frac{-1}{5}=ar
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r
subsituting -1/5 for ar
\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r
which simplifies to
\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for ax^2+bx+c=0
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}
so
for 2r²-5r+2=0
a=2
b=-5
c=2

r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}
r=\frac{5 \pm \sqrt{25-16}}{4}
r=\frac{5 \pm \sqrt{9}}{4}
r=\frac{5 \pm 3}{4}
so
r=\frac{5+3}{4}=\frac{8}{4}=2 or r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}

use them to solve for the value of a
\frac{-1}{5}=ar
\frac{-1}{5r}=a
try for r=2 and 1/2
a=\frac{-1}{10} or a=\frac{-2}{5}


test each
for a=-1/10 and r=2
a+ar+ar²=\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}
it works

for a=-2/5 and r=1/2
a+ar+ar²=\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}
it works


both have the same terms but one is simplified

the 3 numbers are \frac{-2}{5}, \frac{-1}{5}, and \frac{-1}{10}
6 0
3 years ago
What % of 400 = 193
kondor19780726 [428]
(193/400 )x100 equals 48.25 %
8 0
3 years ago
Read 2 more answers
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