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Eduardwww [97]
3 years ago
6

2.09 as an percent and a mixed number

Mathematics
2 answers:
Roman55 [17]3 years ago
7 0
29 percent and. mixed number you take away the 0 and move the point 2 places to get 29.
fredd [130]3 years ago
3 0
Mixed number= 2 9/100

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the perimeter of a rectangle if the width is w centimeters and the length is 3 cm more than twice the width
lianna [129]
L being the length, W being the width.

So:

if the Length is 8cm more than twice the width, we have:

2W+8

so it's:

perimeter of a rectange = 2(2W+8)+2W

You asked me not to simplify it, so that should be your answer.
4 0
3 years ago
Will this happen in avenger 4?
Marizza181 [45]

In chess, the Endgame is where you sacrafice pawns, or in this case, minor characters in order to get a powerful piece back. You can leave some pawns in battle while regaining power pieces. The pawns sacraficed were Peter, Stephen, Bucky, Drax, T'challa. Mantis, etc. While leaving behind two pawns: Nebula, and Bruce Banner. Normally I like to think of the Hulk as a Rook, but since he's completely useless at the moment, he's a pawn. Nebula's fairly worthless, so she's a pawn. Thanos is playing with all power pieces and one pawn: Gamora. He sacraficed his pawn in order to complete his queen equivilence: the gauntlet. Now he's playing with all power pieces, while the Avenger's have sacraficed their pawns in order to get their queen: Captain Marvel, who in turn will wage war on Thanos only to find that a pawn has made it across the board and turned into the Hulk, and fights side by side the original Avengers to get the soul stone, revive Tony, who probably dies, get their friends home, welcome new friends, and kill Thanos.

Sorry about the rambling. I'm not even sure if I got to the point.

4 0
3 years ago
Please help me as soon as posable!! In hurry!!(24 points)
attashe74 [19]

The sequence is geometric, so

a_n = r a_{n-1}

for some constant r. From this rule, it follows that

a_3 = r a_2 \implies 20 = 2r \implies r = 10

and we can determine the first term to be

a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15

Now, by substitution we have

a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots

and so on down to (D)

a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15

(notice how the exponent on r and the subscript on a add up to n)

4 0
2 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

5 0
2 years ago
0.21 times 10 to the power of 6 standard form
skelet666 [1.2K]

Answer:

0.000000210 x 10^{6}=0.21

7 0
3 years ago
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