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3 years ago

I can’t find the difference

Mathematics

2 answers:

Shalnov [3]3 years ago

6 0

Answer:

4/8

Step-by-step explanation:

Ad libitum [116K]3 years ago

3 0

Answer:

6/8

Step-by-step explanation:

6/8 - 0 = 6/8

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Help please idk what to do

stiks02 [169]

Step-by-step explanation:

solve the ineq first then plot on the number line so,

-2(4x + 5) ≤ 30

-8x - 10 ≤ 30

-8x ≤ 40

x ≥ -5

therefore, option A is correct.

Topic: Inequalities

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

4 0

3 years ago

8. Mitchell bought 600 shares of Centerco two years ago $34.50 per share. He sold them yesterday for $38.64 per share.

g100num [7]

Answer:

a. percentage increase in price per share = 12%

b. The total purchase price for the 600 shares is $20,700

c. The profit for the 600 shares is $2,484

d. The profit for the 600 shares is $2,484

Step-by-step explanation:

a. Initial price per share = $34.50

Current price per share = $38.64

Change or increase in price = $38.64 - $34.50 = $4.14

percentage increase in price per share = 12/34.50 x 100% = 12%

b. Total number of shares = 600

Price = $34.50

The total purchase price for the 600 shares = ($34.5x600) = $20,700

c. Total cost of 600 shares = ($34.5x600) = $20,700

Total revenue from sales = ($38.64x600) = $23,184

Profit from the 600 shares = Total selling price - total cost price

= $23,184 - $20,700 = $2,484

d. Total cost of 600 shares = ($34.5x600) = $20,700

Total revenue from sales = ($38.64x600) = $23,184

Profit from the 600 shares = Total selling price - total cost price

= $23,184 - $20,700 = $2,484

7 0

3 years ago

(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)

ladessa [460]

Answer:

7x⁴ + 5x³ + 7x² + 6x + 5

Step-by-step explanation:

The given expression is

(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)

The first step is to open the brackets by multiplying each term inside each bracket by the term outside each bracket. Since the term outside each bracket is 1, the expression becomes

5x⁴ + 5x³ + 4x - 9 + 2x⁴ + 7x² + 2x + 14

We would collect like terms by combining each term with the same exponent or raised to the same power. The term would be arranged in decreasing order of the exponents. It becomes

5x⁴ + 2x⁴ + 5x³ + 7x² + 4x + 2x - 9 + 14

7x⁴ + 5x³ + 7x² + 6x + 5

7 0

4 years ago

F. one die is rolled 3 times. what is the chance of getting no 2's?

aniked [119]

6^3 = 216. When using chance, take the number of outcomes(six for a die) and raise it to the power of the number of repetitions

6 0

3 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

4 years ago