1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ladessa [460]
3 years ago
7

An equation is shown below:

Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0
I hope this helped I've only done part A

You might be interested in
What is the factored form of x^3-1
polet [3.4K]

Answer:

the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

Step-by-step explanation:

We need to find factors of x^3 -1

x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\

So, the factors of x^3-1 are x^3 -1 = (x-1) (x^2 +x+1)\\

7 0
3 years ago
The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s
Molodets [167]

Answer:

  500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

  f(x,y)=4x+2y\\g(x,y)=2x^2+y-4

The Lagrangian is ...

  \mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2

  \dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5

Since x and y are in thousands, maximum profit is to be had when the company produces ...

  500 Type A souvenirs, and 3500 Type B souvenirs

3 0
3 years ago
Help no good at maths
lara [203]
We know that all angles of a triangle equal 180 when added together. We have two angle measures which are 3/2x and 1/2x
***3/2x + 1/2x + x = 180 degrees***
For the other way you can switch around the positions of the angles in the equation as long as the = stays 180 so like
X + 3/2x + 1/2x = 180
180 + x + 1/2x + 3/2x
Or maybe change the 3/2x to 1 1/2x
8 0
3 years ago
Which best describes the clusters in the data set? Number of Fish in Each Tank at the Pet Store A dot plot going from 10 to 15.
Paul [167]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write an Equation in Slope Intercept form for the line described:
svetlana [45]

Answer:

y=-2x+5

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(5-0)/(0-2.5)

m=5/-2.5

m=-2

y-y1=m(x-x1)

y-0=-2(x-2.5)

y=-2(x-2.5)

y=-2x+5

Please mark me as Brainliest if you're satisfied with the answer.

7 0
3 years ago
Other questions:
  • Enter a digit in each box to complete the division problem.
    7·1 answer
  • there is this really annoying girl next tom= me and i want to bachhand her in the face SOMEONE PLEASE HELP ME I NEED TO NOT HIT
    8·1 answer
  • The figure shows a carpeted room. How many square feet of the room are carpeted?
    5·2 answers
  • Round 593 to nearest ten<br> Also are you in 2nd grade cause I am in 3rd
    6·2 answers
  • Find the distance between<br> (-3,5) and (4,-2)
    12·1 answer
  • Please help? At least just for part A.
    10·1 answer
  • Factorise fully 9b-3b2
    15·1 answer
  • I think it’s the third one
    15·2 answers
  • What is the solution to this system?
    13·1 answer
  • Evaluate the equation: 1 2/3 - t = 1/4
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!