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Svetach [21]
3 years ago
6

What is the x-intercept and y-intercept of the linear equation 3x-6y=2

Mathematics
1 answer:
sukhopar [10]3 years ago
8 0

Answer:

The x-intercept is 2/3 and the y-intercept is -1/3

Step-by-step explanation:

In order to find this, we need to note that the x-intercept is the value of x, when y = 0. So we plug in y = 0 and see what the x value is.

3x - 6y = 2

3x - 6(0) = 2

3x = 2

x = 2/3

The y-intercept is the opposite. It is the y value when x = 0. So we do the same with the other term.

3x - 6y = 2

3(0) - 6y = 2

-6y = 2

y = -2/6

y = -1/3

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Melissa the trainer has two solo workout plans that she offers her clients: Plan A and Plan B. Each client does either one or th
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on Wednesday,

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multiply equation one by $4$ and subtract equation two from it

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3 years ago
The radius of a circle is 9 1/4 mm. what is the circumference in terms of pi?
kirill [66]
The formula to find the circumference of a circle is C=2*pi*r.
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4 0
4 years ago
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How much was $500 invested at 6% interest compounded monthly be worth after four years
bogdanovich [222]
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3 0
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Samuel consumed 2129 calories of food on Monday, 2348 calories on Tuesday, and 1863
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8 0
3 years ago
Please help me i don’t understand this question at all.
Maru [420]

9514 1404 393

Answer:

  D.

Step-by-step explanation:

The wording "when x is an appropriate value" is irrelevant to this question. That phrase should be ignored. (You may want to report this to your teacher.)

When you look at the answer choices, you see that all of them are negative except the last one (D). When you look at the problem fraction, you see that it is positive.

The only reasonable choice is D.

__

Your calculator can check this for you.

  √12/(√3 +3) ≈ 3.4641/(1.7321 +3)

  = 3.4641/4.7321 ≈ 0.7321 = -1 +√3

__

If you want to "rationalize the denominator", then multiply numerator and denominator by the conjugate of the denominator. The conjugate is formed by switching the sign between terms.

  \displaystyle\frac{\sqrt{12}}{\sqrt{3}+3}=\frac{\sqrt{12}}{(\sqrt{3}+3)}\cdot\frac{(\sqrt{3}-3)}{(\sqrt{3}-3)}=\frac{\sqrt{36}-3\sqrt{12}}{3-9}\\\\=\frac{6-3\cdot2\sqrt{3}}{-6}=\boxed{-1+\sqrt{3}}

_____

<em>Additional comment</em>

We "rationalize the denominator" in this way to take advantage of the relation ...

  (a -b)(a +b) = a² -b²

Using this gets rid of the irrational root in the denominator, hence "rationalizes" the denominator.

We could also have multiplied by (3 -√3)/(3 -√3). This would have made the denominator positive, instead of negative. However, I chose to use (√3 -3) so you could see that all we did was change the sign from (√3 +3).

3 0
3 years ago
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