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Reil [10]
3 years ago
8

A rectangle has a height of 4 and a width of x^2+3x+2

Mathematics
1 answer:
Mashutka [201]3 years ago
8 0
Base times height 4x^2+12x+8
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F(x)=−x+2, find f(0)
madreJ [45]

Answer:

find \: f(0) \\  \\ f(x) =  - x + 2 \\ f(0) =  - (0) + 2 \\ f(0) =  - 0 + 2 \\ f(0) = 2

7 0
2 years ago
Asa saves dimes and quarters so that he will have exact change for he bus. He dabs and then dumps the container that he has been
koban [17]

Asa has 15 dimes and 32 quarters.

Step-by-step explanation:

Given,

Total coins = 47

Worth of coins = $9.50 = 9.50*100 = 950 cents

1 dime = 10 cents

1 quarter = 25 cents

Let,

Number of dimes = x

Number of quarters = y

According to given statement;

x+y=47      Eqn 1

10x+25y=950   Eqn 2

Multiplying Eqn 1 by 10

10(x+y=47)\\10x+10y=470\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(10x+25y)-(10x+10y)=950-470\\10x+25y-10x-10y=480\\15y=480

Dividing both sides by 15

\frac{15y}{15}=\frac{480}{15}\\y=32

Putting y=32 in Eqn 1

x+32=47\\x=47-32\\x=15

Asa has 15 dimes and 32 quarters.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/2670657
  • brainly.com/question/2821386

#LearnwithBrainly

7 0
3 years ago
Please help, I'll mark Brainiest. It's 8th grade math
yawa3891 [41]

Answer:

(-5, 2)

Step-by-step explanation:

<u>plug x into the equation x - 5y = -15</u>

-5 - 5y = -15

add 5 to both sides: -5y = -10

divide by -5: y = 2

7 0
3 years ago
Read 2 more answers
Write the function for the following chart,
timurjin [86]
Dy/dx=1/2, 1/2, 1/2 etc

So this is a linear equation of the form y=mx+b where m=dy/dx=1/2 so

y=x/2 +b, now we can use any point to solve for the y-intercept, "b", I'll use (7,0)

0=7/2 +b

b=-7/2 so

y=x/2-7/2

y=(x-7)/2
7 0
3 years ago
There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl
insens350 [35]

We're told that

P(A\cap B)=0.15

P(A\cup B)^C=0.06\implies P(A\cup B)=0.94

P(B\mid A)=P(B^C\mid A)=0.5

where the last fact is due to the law of total probability:

P(A)=P(A\cap B)+P(A\cap B^C)

\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)

\implies 1=P(B\mid A)+P(B^C\mid A)

so that B\mid A and B^C\mid A are complementary.

By definition of conditional probability, we have

P(B\mid A)=P(B^C\mid A)

\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}

\implies P(A\cap B)=P(A\cap B^C)

We make use of the addition rule and complementary probabilities to rewrite this as

P(A\cap B)=P(A\cap B^C)

\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)

\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)

\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]

\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]

\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C

\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)

By the law of total probability,

P(B)=P(A\cap B)+P(A^C\cap B)

\implies P(A^C\cap B)=P(B)-P(A\cap B)

and substituting this into (*) gives

2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]

\implies P(B)=P(A\cup B)-P(A\cap B)

\implies P(B)=0.94-0.15=\boxed{0.79}

8 0
3 years ago
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