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Nimfa-mama [501]
3 years ago
12

Find the exact value of cos ⁡ A cosA in simplest radical form.

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

cosA =sinA

Step-by-step explanation:

..... . ......... ....

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*^%Brainliest 15 pounds Question 5 (2 points)
galben [10]

Answer:

0

Step-by-step explanation:

Separate into two parts

\frac{4xy^{3} }{2xy^{2} }  +  \frac{8x^{2} {y}^{5} }{2x {y}^{2} }

Simplify:

This is for the first fraction

\frac{4x {y}^{3} }{2x {y}^{2} }  = (4 \div 2)(x \div x)( {y}^{3}  \div  {y}^{2} )

2(1)( {y}^{3 - 2} )

2{y}

Now for the second fraction:

\frac{8 {x}^{2} {y}^{3}  }{2x {y}^{2} }  = ( 8 \div 2)( {x}^{2}  \div x)( {y}^{5}   \div   {y}^{2} )

4( {x}^{2 - 1} )( {y}^{5 - 2} )

4x {y}^{3}

Add both parts together

2y + 4x {y}^{3}

To turn this into the said formula, that would become:

2 {x}^{0}  {y}^{1}  + 4 {x}^{1}  {y}^{3}

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

4 0
3 years ago
How many significant digits are in thus number 74.30
goblinko [34]

Answer:

3

Step-by-step explanation:

all numbers except from zero

that would mean 7 4 and 3

so there would be 3 significant figures

I hope it goes well

7 0
3 years ago
Allen is trying to buy sneakers he has $50 to spend he finds a pair that he really likes that cost $58 if he has a 20% coupon ca
svetoff [14.1K]
First you would multiply 58 by .20 and you would receive 11.6
next you would subtract 11.y from 58 and get 46.4
so yes Allen can afford the sneakers
4 0
3 years ago
A conjecture and the two-column proof used to prove the conjecture are shown.
aliina [53]

Answer: the statements and resons, from the given bench, that fill in the blank are shown in italic and bold in this table:

    Statement                                                        Reason

1. K is the midpoint of segment JL                      Given

2. segment JK ≅ segment KL                             <em>Definition of midpoint</em>

3. <em>L is the midpoint of segment KM</em>                 Given

4. <em>segment KL ≅ segment LM</em>                           Definition of midpoint

5. segment JK ≅ segment LM                           Transitive Property of

                                                                             Congruence


Explanation:


1. First blank: you must indicate the reason of the statement "segment JK ≅ segment KL". Since you it is given that K is the midpoint of segment JL,  the statement follows from the very <em>Definition of midpoint</em>.

2. Second blank: you must add a given statement. The other given statement is <em>segment KL ≅ segment LM</em> .

3. Third blank: you must indicate the statement that corresponds to the definition of midpoint. That is <em>segment KL ≅ segment LM</em> .

4. Fourth and fith blanks: you must indicate the statement and reason necessary to conclude with the proof. Since, you have already proved that segment JK ≅ segment KL and segment KL ≅ segment LM it is by the transitive property of congruence that  segment JK ≅ segment LM.

5 0
4 years ago
Read 2 more answers
Review the graph of function f(x).
s344n2d4d5 [400]

The two limits when x tends to zero are:

\lim_{x \to \ 0^-}  f(x) = 1\\\\ \lim_{x \to \ 0^+}  f(x) = 0

<h3 /><h3>How to get the limits when x tends to zero?</h3>

Notice that we have a jump at x = 0.

Then we can take two limits, one going from the negative side (where we will go along the blue line)

And other from the positive side (where we go along the orange line).

We will get:

\lim_{x \to \ 0^-}  f(x) = 1\\\\ \lim_{x \to \ 0^+}  f(x) = 0

Notice that the two limits are different, that means that the function is not a continuous function.

If you want to learn more about limits:

brainly.com/question/5313449

#SPJ1

6 0
2 years ago
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