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JulsSmile [24]
3 years ago
12

Shape that s not trapezoid

Mathematics
2 answers:
Temka [501]3 years ago
6 0

Answer:ill help

Step-by-step explanation:

Trapezoid.

Trapezium (BrE) Trapezoid (AmE)

Trapezium or trapezoid

Type quadrilateral

Edges and vertices 4

neonofarm [45]3 years ago
3 0

Answer:hexagon square

Step-by-step explanation:

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Find the length of the third side. If necessary, write in simplest radical form.
Angelina_Jolie [31]

Answer:

the length of the missing side is 2

Step-by-step explanation:

Use a^2 + b^2 = c^2

a = 4

b = ?

c = 2sqrt5

4^2 + b^2 = (2sqrt5)^2

16 + b^2 = 20

subtract 16 from both sides

b^2 = 4

take the sqrt of both sides

b = 2

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Which pair of numbers is relatively prime?
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B I’m pretty sure sorry if wrong
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Ulleksa [173]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Since it's a Trapezoid with its non - parallel sides equal to one another,

\qquad \sf  \dashrightarrow \:\angle A + \angle P = 180

[ By forming co - interior angle pair ]

\qquad \sf  \dashrightarrow \:\angle A +100 = 180

\qquad \sf  \dashrightarrow \:\angle A = 180 - 100

\qquad \sf  \dashrightarrow \:\angle A = 80

Now, similarly,

\qquad \sf  \dashrightarrow \:\angle A + \angle R = 180

\qquad \sf  \dashrightarrow \: \angle R + 80 = 180

\qquad \sf  \dashrightarrow \: \angle R  = 100

Similarly,

\qquad \sf  \dashrightarrow \angle K + \angle R = 180

\qquad \sf  \dashrightarrow \angle K + 100 = 180

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Help me please help me
blsea [12.9K]
Check the picture below.

8 0
3 years ago
Ya idk how to do this plz help explain if you can
Svet_ta [14]

Answer:

  92 attendees had activity cards

Step-by-step explanation:

Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...

  7x +10(130 -x) = 1024

  7x +1300 -10x = 1024 . . . . eliminate parentheses

  -3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300

  x = 92 . . . . . . divide by 3

92 students with activity cards attended the dance.

_____

<em>Comment on the solution</em>

Often, you will see such a problem solved using two equations. For example, they might be ...

Let 'a' represent the number with an activity card; 'w' the number without. Then ...

  • a+w = 130 . . . . the total number of students
  • 7a +10w = 1024 . . . . the revenue from ticket sales

The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...

  w = 130-a

and making the substitution into the second equation gives ...

  7a +10(130 -a) = 1024

This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.

5 0
3 years ago
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