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sasho [114]
3 years ago
8

Which of the following decimals is equivalent to three and ten hundreths?

Mathematics
2 answers:
Tom [10]3 years ago
6 0
C.3.01
the three is a whole number
and is the decimal
ten hundredths is .01 (the 1 is in the hundredths place)
together 3.01
9966 [12]3 years ago
4 0
3.01 is the correct answer

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If two sides of a triangle measure 12 and 7, which cannot be the perimeter of the triangle?
ser-zykov [4K]
Hi,
Let assume x the 3th side.
x<12+7==> x<19
12<x+7==>x>5
So 5<x<19==> 5+7+12<x+7+12<19+7+12
==>24<x<38
Answer d.

8 0
4 years ago
Please someone help me out
hichkok12 [17]

Answer:

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Hope this helps :)

3 0
3 years ago
What can be concluded about the graphed polygon? mc013-1.jpg The polygon is a rectangle. Adjacent sides of the polygon are perpe
Usimov [2.4K]
From the given graph, the image is a trapezoid.
Therefore,
The first option, "t<span>he polygon is a rectangle" is incorrect.
The second option "</span><span>Adjacent sides of the polygon are perpendicular." cannot be true as well because trapezoid has one the adjacent sides which is not perpendicular.
Third option" </span><span>Opposite sides of the polygon are parallel", this can't be true as well because only two sides are parallel.
Fourth option " </span><span>The slope of side c is 0.", this is true because line c is a horizontal line with zero rise and maximum run. Therefore,
Slope = 0 </span>÷ 9
<span>          = 0

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5 0
4 years ago
Read 2 more answers
Emma invested $41,000 in an account paying an interest rate of 2.6% compounded monthly. Assuming no deposits or withdrawals are
kvasek [131]

Answer: it will take 7 years for the value of the account to reach $49,300

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $41000

A = $49300

r = 2.6% = 2.6/100 = 0.026

n = 12 because it was compounded 12 times in a year.

Therefore,

49300 = 41000(1 + 0.026/12)^12 × t

49300/41000 = (1 + 0.0022)^12t

1.2024 = (1.0022)^12t

Taking log of both sides of the equation, it becomes

Log 1.2024 = 12t × log 1.0022

0.08 = 12 × 0.00095 = 0.0114t

t = 0.08/0.0114

t = 7 years

8 0
3 years ago
Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
2 years ago
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