Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
3/10=0.3=30%
725/1000=0.725=72.5%
4/10=0.4=40%
This is middle school work woah
Answer:
m∠3 = 119°
Step-by-step explanation:
All the angles must equal 360° when added together. You have two known angles that are right next to each other. If you add m∠1 and m∠2, 119 + 61, it is equal to 180°. This means that m∠3 and m∠4 must be equal to 180° as well and since there are only two lines, it is safe to assume that opposing angles are the same so m∠1 = m∠3 and m∠2 = m∠4.
(x+y)^2=x^2+y^2+2xy=73+2*24=73+48=121
⇒ (x+y)^2=121
