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kolbaska11 [484]
3 years ago
5

PLEASE, I NEED THIS NOW!!!!

Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

For the first one

x= About 32.02

y= About 27.58

z= About 55.16

For the second one

x= 6

y= 12

z= about 16.97

Step-by-step explanation:

Their all really simple

These are special right triangles, a 45, 45, 90 and a 30, 60, 90 triangle. The formla for these triangles are shown in the picture below.

Now for the first one ]

Lets find Z first

Now this is a 45 special right triangle so we know the other side s 39 but the hypotenuse is n\sqrt{2} (I’m using N becuase x and y is taken) So n is basically 39 (look at the image below) and just solve that. Now for x and y. We know its a 30, special right triangle. We know that 39 here is already the answer for  N\sqrt{3} so make an equation to find the n and you’ll get 27.58 for y. Now For x, its just doubled the y.

For the second one this is easier

We know that the x is (6) becuase its already in the radical number, now to find the hypotnuse, we double that and get 12. Now we know what y is becuase since the 2nd triangle is a 45/45/90, we know that 12 is y, the hypotnuse is just N\sqrt{2} and we just plug in the n with 12 and solve it!

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Answer:

Brother is 70.5 and sister is 64.5

Step-by-step explanation:

you will need to set up a simple equation and give out variables.

Girls age = 6-x

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the you will take those 2 and add them and place them equal to 135:

6-x+x=135

6-2x+6=135+6

The 6 cancels out

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x=70.5

The brother's age would be 70.5 then and the girl's would be 64.5

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Answer:

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Step-by-step explanation:

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If the area of a rectangle is 64cm squared, how many different perimeters are possible when the dimensions are whole numbers
FinnZ [79.3K]

Answer:

2 different perimeters, 32 cm and 40 cm

Step-by-step explanation:

Given the area of a rectangle is 64 cm squared.

We know, Area of the rectangle is = length x breath

∴  64 = 8 x 8

Hence the sides can be 8 cm by 8 cm.

So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm

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∴  64 = 16 x 4

So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm

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