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3 years ago

Which expression is equivalent to 4(7 + 8)?A) 11+8B) 11+12C) 28+12D) 28+32

2 answers:

7 0

To do this we take the outlier off the parenthesis (the 4) and multiply it by the two numbers inside the parenthesis...

4*7 + 4*8

28+32

Vinil7 [7]3 years ago

4 0

Answer:

D) 28+32

Step-by-step explanation:

4(7+8)=4(15)=60

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I need help with number 3 please and thank you

murzikaleks [220]

So here we're dealing with equivalent fractions.
It's really simple to find the answer, so I'll try to explain the best I can.

2 dogs / 5 cats is really just 2/5.
If we want to find an equivalent fraction, we have to multiply the numerator and the denominator by the same number.

Currently the number of cats is 5, and we need it to be 140. What we need to do is find the number it has to be multiplied by to equal 140, which is 140 divided by 5. 140 divided by 5 is 28, so 5 x 28 = 140!

We need to multiply the denominator (5) by 28, so that we can get 140. What we have now is ?/140.

Like I said, to find an equivalent fraction, we need to multiply the numerator by the same number as we did the denominator, which is 28!

2 x 28 = 56.

So 2/5 is the same as 56/140.

The answer is D) 56 Dogs/140 Cats.

Hope this helps!
If you're confused about anything leave me a reply and I'll try to explain the best that I can!

3 0

2 years ago

Calculate each or quotient 2 2/5 x3 1/3=

My name is Ann [436]

8

You multiply the numbers

6 0

3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

Find the answer to the nearest tenth.

Fed [463]

Area=1/2bh h=altitude b=legnth of base b is 3 times h b=3h divide by 3 b/3=h area=1/2bh subsitute b/3 for h 54=1/2(b)(b/3) multiply bothsides by 2/1 108=b(b/3) 108=(b^2)/3 multipy both sides by 3 324=b^2 square root boh sides 18=b legnth of base=18

7 0

3 years ago

1/4 cup equals how many pounds?

Leno4ka [110]

1/4 cup equals 0.25 lbs.

6 0

3 years ago

Which expression is equivalent to 4(7 + 8)?A) 11+8B) 11+12C) 28+12D) 28+32​

Which expression is equivalent to 4(7 + 8)?A) 11+8B) 11+12C) 28+12D) 28+32