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Lostsunrise [7]
3 years ago
6

Sam Houston's Arms

Mathematics
1 answer:
OLga [1]3 years ago
7 0

Answer:

The length of the statue's arm is<u> 26.22 ft.</u>

Step-by-step explanation:

Let the length of the statue's arm be 'x'.

Given:

Height of statue is, H=67\ ft

Height of male is, h=5\ ft\ 9\ in=5\ ft+\frac{9}{12}\ ft=5+0.75=5.75\ ft

Length of the male's arm is, l=27\ in=\frac{27}{12}=2.25\ ft

Now, as the size of Sam Houston's statue is proportional to that of an adult male, therefore, their heights and arm lengths will also be in proportion. So,

\frac{H}{h}=\frac{x}{l}\\x=\frac{H}{h}\times l

Now, plug in the given values and solve for 'x'.

x=\frac{67}{5.75}\times 2.25\\x=26.22\ ft

Therefore, the length of the statue's arm is 26.22 ft

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