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Readme [11.4K]
4 years ago
5

Assume that block A is accelerating with block B at a rate of 0.800 m/s2 along a frictionless surface. What is the mass of both

A and B?
A. 145 kg

B. 120 kg

C. 105 kg

D. 125 kg

Physics
1 answer:
zlopas [31]4 years ago
6 0

Answer:

The mass of A and B together is 125kg

Explanation:

To solve this problem, we set up the equations expressing the net force acting on A and B (forces acting to the right are +, those acting to the left are -):

m_B\cdot a_B=F - F_{fr}\\m_A\cdot a_A = F_{fr}\\a_A = a_B

The net force acting on B is due to the acting pull force 100N less friction force caused by A. The net force on A is due to the friction force caused by the block B. Since we know both blocks accelerate at the same rate, the system can be solved easily:

(m_B+m_A)\cdot a_B=F\\(m_B+m_A)\cdot 0.800 \frac{m}{s^2}=100N\implies\\m_B+m_A = \frac{100N}{0.800\frac{m}{s^2}}kg= 125kg

Of course, alternatively, in this very simple case you could consider A+B a single object being pulled with 100N, and obtain the same results by diving the pull force by the acceleration.

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When two things are the same temperature:
Rus_ich [418]

Answer:

its obviously D if all the other says "incorrect answer" XD

Explanation:

4 0
3 years ago
A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
erastovalidia [21]

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

5 0
4 years ago
At the beginning of a unit on forces, Ms. Alton is leading a class discussion asking her students
VMariaS [17]

Answer:

(iv), (v), (vi) would be incorrect.

Explanation:

(iv) Force isn't transferred from one colliding object to another, but momentum can be.

(v) An object doesn't stop immediately a force stops acting on it. Think of a thrown ball.

(vi) For an object not to move, it means that the net force on the object is zero, and not necessarily that there are no forces acting on the object. For example, an object could be pushed on one side, and be pushed on the other side with an equal force in the opposite direction. The forces would cancel each other and the net force would be zero.

The rest should be correct.

6 0
3 years ago
A scientific theory is_____.
natta225 [31]

Answer:

B. A well-tested explanation for a widely accepted hypothesis

Explanation:

This is true about a scientific theory going by the fact of it being a well tested explanation. For example, in one of the Newtons law of motion which he stated to be<em> "To every action, there is equal and opposite reaction", </em><em>the hypothesis has been known till he was able to offer a well tested explanations with calculations showing that, it was actually true.</em>

6 0
3 years ago
A heat pump that operates on the ideal vapor-compression cycle with refrigerant-134a is used to heat a house. The mass flow rate
Savatey [412]

(a)  

Use “saturated refrigerant-134a pressure tableâ€, to find $ , h ,           and of refrigerant-134a, at 320kPa (P) .

     h_{1} h_{g} = 251.93kJ/kg

    s_{1} (s_g}) =0.93026 kJ/kg-K

    v_{1}(v_{g}) =0.063681 m/kg

we solve h_{6} ,

h_{6} = 282.62 kj/kg

h_{3} (h_{f)} = 127.25 kJ/kg

We use this formula for finding Q_{n}

Q_n}  =( h_{2} - h_{3}  )

      = 38.8 kw

(b)

Find the COP of the heat pump (COP_{R}) .

(COP_{R})  = q_{L} /w_{in}

COP_{R} = (282.62 -127.25) / (282.62-251.93)

          = 5.06

What is evaporator pressures ?

Valves for regulating evaporator pressure

Although the compressor suction pressure may be lower, evaporator pressure regulation (EPR) valves can be employed in the suction line to prevent the evaporator pressure from dropping below a set or controlled value.

An EPR valve is used for the following tasks:

1. Prevent potential damage to a liquid chilling evaporator from the liquid freezing.

2. Prevent frost from accumulating on an air-cooling evaporator when it is near freezing point or when operation cannot be interrupted by a brief failure.

3. Permit the operation of two or more evaporators with the same compressor at various load temperatures.

4. Vary the evaporator pressure in accordance with a fluctuating load that is managed by the load temperature.

Learn more about evaporator pressures visit this link:

brainly.com/app/ask?q=What+is+evaporator+pressures+

#SPJ4

7 0
1 year ago
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