Answer:
F = 789 Newton
Explanation:
Given that,
Speed of the car, v = 10 m/s
Radius of circular path, r = 30 m
Mass of the passenger, m = 60 kg
To find :
The normal force exerted by the seat of the car when the it is at the bottom of the depression.
Solution,
Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.



N = 788.6 Newton
N = 789 Newton
So, the normal force exerted by the seat of the car is 789 Newton.
Answer:
60m/s
Explanation:
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Answer:
A. Tangential velocity of the 100cm position = 1.5g
B. Tangential velocity at 66.67cm equals acceleration due to gravity.
Explanation:
I = I(cm) × M.(1/2)²
I = 1/12.m.(1)² + m(1/2)²
= 1/3m
= 1/2.mg = mg/2
Therefore, ∆= I×¶
¶ = ∆/I = (mg/2)/(mg/3) = 3g/2
A. Tangential acceleration of the 100cm position = ∆ × 1
= 1×3g/2 = 1.5g
B. At g = ¶ × 3g/2
¶ = 2/3m
= 2/3×100
= 200/3
Hence, tangential acceleration is equal to = 66.67cm
Answer:
Multiple transformations occur because the chemical energy of the fuel is changed to several forms of energy
Explanation:
In a car engine, multiple energy transformation takes place. The chemical energy storef in fuel is transformed into mechanical energy which helps move the wheels of the vehicle.
The mechanical energy can also be transformed into electrical energy through a sort of dynamo system in vehicles. Stereo players use the electrical energy to produce sound.
We see that multiple energy conversions are common in a motor car.