Which of the following X-Y tables agrees with

Rank in order, from largest to smallest, the magnitudes of the electric field at the black dot. A. 2, 1, 3, 4 B. 1, 4, 2, 3 C. 3

sweet [91]

Given that,

Rank in order from largest to smallest the magnitude of the electric field at block dot.

Electric field :

Electric field is proportional to the charge divided by square of distance.

In mathematically,

$E\propto\dfrac{q}{r^2}$

Where, q = charge

r = distance

If the charge is greater then electric field will be greater.

If the distance is greater then electric field will be smaller.

We need to find the electric field at black dot

According to figure,

(I). The electric field at black dot due to positive charge point q to left. the distance is r.

The electric field will be

$E=\dfrac{kq}{r^2}$

The electric field will be largest.

(II). The electric field at black dot due to positive charge point 2q to left. The distance is 2r.

Then, the electric field will be

$E=\dfrac{k2q}{(2r)^2}$

$E=\dfrac{kq}{2r^2}$

The electric field will be smallest.

(III). The electric field at black dot due to positive charge point 2q to left. The distance is r.

Then, the electric field will be

$E=\dfrac{k2q}{(r)^2}$

The electric field will be very largest.

(IV). The electric field at black dot due to positive charge point q to left. The distance is 2r.

Then, the electric field will be

$E=\dfrac{kq}{(2r)^2}$

$E=\dfrac{kq}{4r^2}$

The electric field will be very smallest.

So, The electric field from largest to smallest will be

$E_{3}>E_{1}>E_{2}>E_{4}$

Hence, The ranking will be 3, 1, 2, 4.

(D) is correct option.

4 0

3 years ago

A sinusoidal wave of wavelength 2.00m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right. At t = 0

Shkiper50 [21]

The frequency and angular frequency are 0.500 Hertz and 3.142 rad/s. respectively.
The angular wave number is equal to 3.142 rad/m.
The wave function for this wave is given by: y = Asin(kx - ωt + Φ).
The equation of motion for the left end of the string is given by: y = 0.100sin(3.142x - 3.142t + 0).
The equation of motion for the left end of the string at x = 1.50 m to the right is equal to y = 0.100sin(4.71 - 3.142t + 0).The maximum speed of any point on the string is 0.3142 m/s.

<h3>How to calculate the frequency and angular frequency?</h3>

First of all, we would determine the frequency of this wave by using this formula:

Frequency = wavelength/speed

Frequency = 0.100/2.00

Frequency = 0.500 Hertz.

For the angular frequency, we have:

Angular frequency, ω = 2πf

Angular frequency, ω = 2 × 3.142 × 0.500

Angular frequency, ω = 3.142 rad/s.

<h3>How to determine the angular wave number?</h3>

Angular wave number, k = 2π/∧

Angular wave number, k = (2 × 3.142)/2.00

Angular wave number, k = 3.142 rad/m.

<h3>How to determine the wave function for this wave?</h3>

Mathematically, the wave function for this wave is given by:

y = Asin(kx - ωt + Φ)

For the equation of motion for the left end of the string, we have:

y = 0.100sin(3.142x - 3.142t + 0)

For the equation of motion for the left end of the string at x = 1.50 m to the right, we have:

y = 0.100sin(3.142x - 3.142t + 0)

y = 0.100sin(3.142(1.5) - 3.142t + 0)

y = 0.100sin(4.71 - 3.142t + 0)

<h3>What is the maximum speed of any point on the string?</h3>

Vy = 0.100sin(- 3.142)cos(3.142x - 3.142t)

Vy ≤ 0.3142 m/s (since cosine varies +1 and -1).

Read more on wave function here: brainly.com/question/11181093

#SPJ4

Complete Question:

A sinusoidal wave of wavelength 2.00 m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right. Initially, the left end of the string is at the origin. Find:

(a) the frequency and angular frequency,

(b) the angular wave number, and

(c) the wave function for this wave.

Determine the equation of motion in SI units for

(d) the left end of the string, and

(e) the point on the string at x = 1.50 m to the right of the left end.

(f) What is the maximum speed of any point on the string?

5 0

2 years ago

Please help and explain if you can

swat32

Answer:

I think it is the last one

Hot air rising and cool air sinking.

Explanation:I am not 100% sure. I just think the hot air rises bc evaporation.

Good luck. : )

5 0

3 years ago

Our primary method for localizing sound in the horizontal plane is ____.?

Papessa [141]

Our primary method for localizing sound in the horizontal plane is to compare the arrival time of sound at each ear.

6 0

3 years ago

A child’s toy sits on the bottom of a swimming pool in which the water depth is d=1.8 m. To a child standing at the pool edge, t

navik [9.2K]

Answer:

Horizontal distance is 1.28 + 2.04 = 3.32 m

Explanation:

Given data:

from below figure

Applying Pythagoras theorem

from Snell's law

$\frac{sin i}{sin r} = \frac{n_2}{n_1} = \frac{\frac{EF}{AB}}{\frac{DE}{BD}}$

$1.33 =\frac{ \frac{2.04}{\sqrt{(3.5 -1.8)^2 + 2.04^2}}}{\frac{x}{\sqrt{1.8^2 + x^2}}}$

solving for x we have

$x^2 = 1.626$

x = 1.28

Horizontal distance is 1.28 + 2.04 = 3.32 m

8 0

3 years ago