Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv
Substitute the suitable values in the above equation.
v₁ = 2.57 m/s
Answer:
Explanation:
u = 150 m/s
R = 800 m
The formula for the horizontal range is
where, θ is angle of projection.
Sin2θ = 0.348
2θ = 20.4°
θ = 10.2°
The range is same for the complementary angles.
So, the other angle is 90 - 10.2 = 79.8°
Answer:
c) time
Explanation:
time is a fundamental quantity from which other quantities are derived
In order to answer this, we will set up a simple ratio as such:
1 calorie = 4.184 joules
1 kilocalorie = 1000 calories
1 kilocalorie = 4,184 joules
250 kilocalories = x joules
Cross multiplying the second and third equations, we get:
x joules = 4,184 * 250
250 kilocalories are equivalent to 1,046 kJ
The observer can conclude that the sound is moving away from them and that its speed is increasing.
