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Vsevolod [243]
4 years ago
5

Find the indicated probability by using the general addition rule. For a person selected randomly from a certain​ population, ev

ents A and B are defined as follows. Aequalsevent the person is male Bequalsevent the person is a smoker For this particular​ population, it is found that Upper P (Upper A )equals 0.48 comma Upper P (Upper B )equals 0.23 comma and Upper P (Upper A & Upper B )equals 0.12 . Find Upper P (Upper A or Upper B ).
Mathematics
1 answer:
kumpel [21]4 years ago
4 0

Answer:

Upper P (Upper A or Upper B ) = 0.59

Step-by-step explanation:

We have that:

P(A) = 0.48

P(B) = 0.23

P(A \cap B) = 0.12

The question asks:

P(A \cup B)

According to the set theory, it is

P(A \cup B) = P(A) + P(B) - P(A \cap B)

Then

P(A \cup B) = 0.48 + 0.23 - 0.12 = 0.59

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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
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Answer:

(a) The probability that a randomly selected adult is either overweight or obese is 0.569.

(b) The probability that a randomly selected adult is neither overweight nor obese is 0.431.

Step-by-step explanation:

Let <em>A</em> = a person is over weight and <em>B</em> = a person is obese.

The information provided is:

An adult is considered overweight if the BMI ≥ 25 but BMI < 30.

An obese adult will have a BMI ≥ 30.

According to the range of BMI the events A and B are independent.

P (A) = 0.331 and P (B) = 0.357.

(a)

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P (A ∪ B) = P (A) + P (B) - P (A ∩ B)

               = P (A) + P (B) - P (A)×P (B)

               =0.331+0.357-(0.331\times0.357)\\=0.569833\\=0.569

Thus, the probability that a randomly selected adult is either overweight or obese is 0.569.

(b)

Compute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(A^{c}\cup B^{c})=1-P(A\cup B)=1-0.569=0.431

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.431.

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4 years ago
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