X+y+z=51
y=2z
z=9+x
subsitute those
x+2z+9+x=51
x+2(9+x)+9+x=51
x+18+2x+9+x=51
4x+27=51
minus 27 both sides
4x=24
divide by 4
x=6
sub back
z=9+x
z=9+6
z=15
y=2z
y=2(15)
y=30
the numbers are
6,30,15
Answer:
90 bag
Step-by-step explanation:
no of bags will he have left=213-123
=90 bags of candy
3x-5x+3 Answer:
Step-by-step explanation: