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2 years ago

Find the sum of the geometric sequence. (1, 1/1, 1/4, 1/8, 1/16)

1 answer:

3 0

Hello :
<span>the sum of the geometric sequence. (1, 1/2, 1/4, 1/8, 1/16) is :
s = 1× (1-(1/2)^5)/(1-(1/2))=(1-(1/32)/(1/2) =(31/32)/(1/2) =31/16</span>

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PLSSS HELP IF YOU TURLY KNOW THISS

xxMikexx [17]

Answer:

2 1/2

Step-by-step explanation:

Turn both fractions into improper fractions, multiply the whole number by the denominator and add the numerator.

4 3/4

4 * 4 + 3 = 19

19/4

2 1/4

2 * 4 + 1 = 9

9/4

Now since she drank 2 1/4 gallons of juice, subtract 9/4 from 19/4.

19/4 - 9/4 = 10/4

Now turn back into a mixed fraction, do this by putting 4 into ten twice and taking the remainder and putting it as numerator:

4 * 2 = 8

10 - 8 = 2

2 1/2

8 0

2 years ago

Will give brainliest

VikaD [51]

Answer: The number of the adult tickets is 168

Step-by-step explanation: * Lets explain how to solve the problem

- The adults ticket costs $10.50

- The students ticket costs $3.75

- The total money of the opening night is $2071.50

- The equation of the total money earned in the opening night is:

10.50 a + 3.75 b = 2071.50, where a is the number of the adult ticket

and b is the number of the student ticket

- There were 82 students attended

* Lets solve the problem

∵ 10.50 a + 3.75 b = 2071.50

∵ The number of the students attended is 82

∵ b is the number of the students

∴ b = 82

- Substitute the value of b in the equation

∴ 10.50 a + 3.75(82) = 2071.50

∴ 10.50 a + 307.5 = 2071.50

- Subtract 307.5 from both sides

∴ 10.50 a = 1764

- Divide both sides by 10.50

∴ a = 168

∵ a is the number of the adult tickets

∴ The number of the adult tickets is 168

Give credit to ashraf 82

8 0

3 years ago

There are 270 sixth grade students and 45 chaperones going on a field trip. How many students would go with each chaperone if di

Alenkinab [10]

270 ÷ 45 is 6 students per chaperone

5 0

3 years ago

Read 2 more answers

Prime integers between 1and11

Roman55 [17]

Answer:

1,3,5,7,11

Step-by-step explanation:

a prime numb er or integer is a number that can not be multiplied to get to other than x1 so for example the only thing you can do for 3 is 3x1 not anything else especially because you said integer

5 0

3 years ago

Someone please help me??

lapo4ka [179]

The standard equation of a circle with centre (xc,yc) and radius R is given by

$(x-x_c)^2+(y-y_c)^2=R^2$

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore

$(x-x_c)^2+(y-y_c)^2=R^2$
$(x-4)^2+(y-(-3))^2=2.5^2$
$(x-4)^2+(y+3)^2=2.5^2$ or
(x-4)^2+(y+3)^2=6.25

7 0

3 years ago