(2*5*3)+(2*6*3)+(6*3*2) = 102
Answer: Option A
Step-by-step explanation:
A relation between two variables x and y is considered a function if and only if, for each input value x there is only one output value y.
If for an input value
there are two output values
and
then the relation is not a function.
Therefore, to answer this question, identify the table in which each value of x has only one value of y.
You may notice that the option that meets this requirement is option A
Note that in option B, there are two output values 17 and 16 for x = -4.
So this relationship is not a function.
In option C there are 2 output values for x = -5
In option D there are 2 output values for x = -11
The answer is C, because your homework assignments (h) is equal to 8 (Amount of assignments in one week) times the number of weeks.
Answer:
1
Step-by-step explanation:
Given the question above :
The probability distribution :
X : ___ 1 ___ 2 ___ 3 ___ 4 ____ 5
P(x): _ 0.1 __ 0.1 __ 0.6 _ 0.1 __ 0.1
The Variance : Var(X) = (Σx²*p(x)) - μ²
μ = E(X) = Σ(X * p(x)) :
Σ(X * p(x)) = (1*0.1)+(2*0.1)+(3*0.6)+(4*0.1)+(5*0.1)
μ = 3
Var(X): [(1^2*0.1)+(2^2*0.1)+(3^2*0.6)+(4^2*0.1)+(5^2*0.1)] - 3²
= 10 - 9
= 1
Hence. Variance = 1
Answer:
I would need the picture please
Step-by-step explanation:
Thank you! Let me know when you've added the question!
You can just give me the height and base.