CosФ=24/25
Sin Ф=7/25 CoseceФ=25/7
TanФ=7/24 cotФ=24/7
SecФ=25/24
Let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23
the integers are 17 , 23 and 34
Answer:
D. This quadratic equation two complex solutions.
Step-by-step explanation:
Equating it with
a = 5, b = 6, c = 2
is negative.
Therefore, this quadratic equation two complex solutions.
None of the choices is correct. -0.38 written as a fraction is -38/100 . It can be reduced to -19/50 .
Answer:
2, sqrt of 7633
Step-by-step explanation:
for now, we'll leave the 3rd side as x
y using the Pythagorean theorem, we can conclude that (1) 48^2+x^2=73^2 or (2) 48^2+73^2=x^2.
1. If we conclude the x isn't the longest, the x would be 3025 which is the sqrt of 55, now is invalid because the 2 smallest sides can't be more than the longest side when they add up 55+48>73 so that is invalid
2. Then, it leaves us with only 1 choice left! concluding that the 3rd side is the longest. Which the answer is sqrt of 7633
