3 years ago

The simplest radical form of the radicand 32

Mathematics

1 answer:

diamong [38]3 years ago

5 0

Your answer is 4 radical 2.

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Y = x + 2<br> y = 3x - 4

exis [7]

Answer:

x=3; y=5

Step-by-step explanation:

y=x+2

y=3x-4

so x+2=3x-4

2x=6

x=3

because y=x+2

x=3

so y=3+2

8 0

2 years ago

A candy machine makes 75 pieces of candy a minute. If a full box of candy holds 8 pieces, how many full boxes does the machine

Hunter-Best [27]

9 hvcitcutdutdutdutdut

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3 years ago

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Please help with 16 and 17 those are hard

notka56 [123]

The answer to number 17 is c

6 0

3 years ago

Write an equation of the line that passes through the given point and has the given slope

vfiekz [6]

The formula is y = mx+b where m is the slope and b is the y intercept.

y = 0x + b
7 = (-6)0 + b
7 = 0 + b
b = 7
y = +7

4 0

3 years ago

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

4 0

2 years ago