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skelet666 [1.2K]
3 years ago
9

Work out the size of x

Mathematics
1 answer:
topjm [15]3 years ago
7 0

Answer:

They are supplementary angles so they add up to make 180°

So you do the reverse

180°-100°=x

80°=x

Step-by-step explanation:

Please give me brainliest

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Calculate the area of this circle please
Anni [7]

Answer:

2289.06 cm

Step-by-step explanation:

the equation for area of a circle is \pi r^{2}

Radius is 1/2 the diameter = 27

3.14 (27^2)=2289.06 cm

4 0
3 years ago
Type in a value that represents as likely as not in a decimal form.
dem82 [27]
Msmsososns lsos s smslsoos
7 0
3 years ago
The density of a fluid is given by the empirical equation rho=70.5 exp(8.27 X 10^-7 P) where rho is density (lbm/ft^3) and P is
jasenka [17]

Answer:

(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf

(b) density = 0.1206g/cm^3

(c) rho = 0.1206exp(8.27×10^-7P)

Step-by-step explanation:

(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf

(b) P = 9×10^6N/m^2

rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3

rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3

(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is

rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)

5 0
3 years ago
Solve each of the following equations using a method other than the Quadratic Formula.
liraira [26]

Answer:

A)

y^2-6y = 0

or, y(y-6) = 0

or, y = 0 or y = 6

B)

n^2+5n+7 = 7

or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)

or, n^2+5n = 0

or, n(n+5) = 0

or, n=0 or n= -5

C)

2t^2-14t+3 = 3

or, 2t^2-14t = 0

or, 2t(t-7) = 0

or, t=0 or t=7

D)

1/3x^2+3x-4 = -4

or, 1/3x^2+3x = 0

or, 1/3x(x+9) = 0

or, x=0 or x= -9

E)

Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.

THANK YOU FOR READING.

8 0
3 years ago
Between which two integers can the square root of 15 be found?
Taya2010 [7]

Answer:

3 and 4

Step-by-step explanation:

Consider squares on either side of 15, that is 9 and 16, so

\sqrt{9} < \sqrt{15} < \sqrt{16}, that is

3 < \sqrt{15} < 4

3 0
4 years ago
Read 2 more answers
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