There are many...since 1 yard is 3 feet, then 12 yards, which is 12 times as much , is 12 x 3 or 36 feet.....
Answer:
He must sell 8 cards to reach the minimum goal.
Step-by-step explanation:
Giving the following information:
He wants to earn more than $50 at the fair.
He sells his cards for $2 and he has already earned $36.
<u>First, we need to calculate the money required to reach the minimum goal:</u>
51 - 36= $15
<u>Now, we write the inequality:</u>
2*x >15
x= number of cards sold.
x>15/2
x> 7.5
He must sell 8 cards to reach the minimum goal.
The length of arc of the given circle, to the nearest hundreth, is: 2.41 units.
<h3>What is the Length of an Arc?</h3>
Length of arc = ∅/360 × 2πr, where the radius of the circle is r, and the reference angle is ∅.
We are given the following:
Radius (r) = 3 units
Reference angle (∅) = 46°
Plug in the values into the length of arc formula:
Length of arc = 46/360 × 2π(3)
Length of arc = 2.41 units.
Therefore, the length of arc of the given circle, to the nearest hundreth, is: 2.41 units.
Learn more about length of arc on:
brainly.com/question/2005046
C (3,1)
There is the answer and also a check to make sure hope this helps
Answer:

And for this case the interpretation for the slope would be that for every unit that the height in inches increase then the weight in pounds increase 6 units.
For the intercept of 135 represent the amount initial amount of weight for the scale.
Step-by-step explanation:
We assume that they use least squares in order to create the regression equation
For this case we need to calculate the slope with the following formula:
Where:
With these we can find the sums:
And the slope would be:
The means for x and y are given by:
And we can find the intercept using this:
For this case we know that the line adjusted is:

And for this case the interpretation for the slope would be that for every unit that the height in inches increase then the weight in pounds increase 6 units.
For the intercept of 135 represent the amount initial amount of weight for the scale.