$\text{The vertex form of a parabola}\\\\y=a(x-h)^2+k\\\\\text{We have the vertex}\ (-2,\ 5)\to h=-2,\ k=5.\\\\\text{Substitute}\\\\y=a(x-(-2))^2+5=a(x+2)^2+5\\\\\text{We have the point}\ (5,\ -4).\\\text{Substitute the coordinates of the point to the equation:}\\\\-4=a(5+2)^2+5\\\\-4=a(7)^2+5\\\\-4=49a+5\qquad|-5\\\\-9=49a\qquad|:49\\\\a=-\dfrac{9}{49}\\\\Answer:\ \boxed{y=-\dfrac{9}{49}(x+2)^2+5}$

5 0

3 years ago

Solve the equation 4.1g+6=2.1g+12.

SSSSS [86.1K]

Answer:

g=3

Step-by-step explanation:

6 0

3 years ago

Fine the value of the x in the triangle shown below.

Sever21 [200]

Answer:

x=28

Step-by-step explanation:

The interior angles of a triangle must add to 180 degrees

Therefore,

79+73+x=180

Combine like terms by adding 79 and 73

152+x=180

To solve for x, get x by itself. Since 152 is being added to x, subtract 152 from both sides. This will cancel the 152, and leave x by itself.

152-152+x=180-152

x=28

So, x is equal to 28 degrees

8 0

3 years ago

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