Question

Please solve all with explanation

Answer 1

Answer:

1. $\frac{x^2}{y^8}$

2 a) $\frac{-49}{2}$

b) 0

3. x = 10

Step-by-step explanation:

1.

$(\frac{x^{-3}y^4}{x^{-2}})^{-2}\\({x^{-3+2}y^4})^{-2}\\({x^{-1}y^4})^{-2}({x^{-1*-2}y^{4*-2})= \frac{x^2}{y^8}$

2. a)

$2 [(\frac{-1}{4}) -12 (-1)^2] - 5[24 +2 (-12)]^2\\2[(\frac{-1}{4}) -12] - 5[24 -24]^2\\2 * [(\frac{-1}{4}) -12] -0\\\frac{-49}{2}$

b)

$-a^2b^2 - 3a^3b^2\\-\frac{1}{9}*1 - 3 * \frac{-1}{27} *1\\-\frac{1}{9} + \frac{1}{9}\\0$

3.

$\frac{3}{4}x + \frac{5}{6} = 5x -\frac{125}{3} \\\frac{5}{6} + \frac{125}{3} = 5x - \frac{3}{4}x\\\frac{5+250}{6} = \frac{20x -3x}{4}\\\frac{255}{6} = \frac{17x}{4}\\x = 10$