All categories

3 years ago

Find the perimeter of the trapezoid

Mathematics

2 answers:

gregori [183]3 years ago

7 0

Please check the picture.

vitfil [10]3 years ago

3 0

ANSWER:38
Explanation:
A(squared)+B(squared)=C(squared)
A(squared)=25
C(squared)=169
P.s- C(squared) is always on the opposite side of the 90degree angle
169-25=144
144=12
13+3+6+4+12=38

You might be interested in

What is the surface area of the rectangular pyramid below?

horrorfan [7]

Answer:

the surface area of the rectangular pyramid below is 300 units2

6 0

3 years ago

Read 2 more answers

What is the variable used to predict another variable called________.A. Independent variableB. Dependent variableC. Moderating v

UkoKoshka [18]

Answer:

A. Independent variable

Step-by-step explanation:

The prediction of a variable can be done if we have the independent variable. Which is the required variable that is used to determine the value of the other variable. The variable to be predicted is dependent on the required variable.

An independent variable can also be referred to as a predictor variable. When its value is known, it can be used to obtain the dependent variable.

7 0

3 years ago

Please Help! (Math)(tanβ)

sertanlavr [38]

Answer:

Find the missing side first.

x = $\sqrt{12^2 - 7^2} = \sqrt{144 - 49} = \sqrt{ 95}$

1) tangent = opposite leg / adjacent leg

tanβ = √95/7
Correct choice is B

2) sine = opposite leg / hypotenuse

sinβ = √95/12
Correct choice is D

7 0

3 years ago

Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

$\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}$

Recall that since both lines are parallel, we have that,

$m_1=m_2$

Thus

$m_2\text{ = 1}$

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

5 0

1 year ago

The most accurate estimation 5+4

MariettaO [177]

The most accurate "estimation" for 5+4 is um... 9

4 0

3 years ago