A merchant bought some shirts for $120. The next day the price charged for each shirt was reduced by $1. The merchant calculated
1 answer:
Answer:
The merchant buys 30 shirts originally.
Step-by-step explanation:
Let us assume that the merchant bought x numbers of shirts in $120.
So, the cost for each shirt is $.
Now, if the cost for each shirt is reduced by 1$, then he would have bought 10 shirts more i.e. (x + 10) shirts in $120.
So, we can write the following equation as
⇒(120 - x)(x + 10) = 120x
⇒ 120x - 10x + 1200 - x² = 120x
⇒ x² +10x - 1200 = 0
⇒ x² + 40x - 30x - 1200 = 0
⇒(x + 40)(x - 30) = 0
⇒ x = - 40 or x = 30
But x can not be negative.
Hence, the merchant buys 30 shirts originally. (Answer)
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Answer:
The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88
The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.
Step-by-step explanation:
Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88
At the null hypothesis, we test if the proportion is of 0.88, that is:
At the alternate hypothesis, we test if this proportion is less than 0.88, that is:
The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88
The test statistic is:
In which X is the sample mean, is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
0.88 is tested at the null hypothesis:
This means that
A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.
This means that
Test statistic:
P-value of the test:
The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.
Looking at the z-table, the p-value of z = -0.68 is of 0.2483.
The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.