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Ivanshal [37]
3 years ago
12

What makes a unit circle distinct from just any circle drawn on the coordinate plane? In your answer use terms like; origin, coo

rdinate plane, x - and y - axes to explain.
Mathematics
2 answers:
Sergio [31]3 years ago
7 0

Answer:

Step-by-step explanation:

The unit circle is a circle with a center at the origin and a radius of 1. The circumference of the circle can be used to represent a number line. This allows trig functions to be thought of as two dimensional functions represented on the coordinate plane with x and y terms, rather than just the ratio of a right triangle.

salantis [7]3 years ago
6 0

Answer:

What makes a unit circle distinct from just any circle drawn on the coordinate plane is that the unit circle starts with the origin finding the radius,It also consists of forming a triangle on the radius with the x-axes,y-axes and 1 which is always the radius on the unit circle which is very different from a coordinate plane.

Step-by-step explanation:

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168

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
The volume of a prism is the product of its height and area of its base, V = Bh. A rectangular prism has a volume of 16y4 + 16y3
Zepler [3.9K]

Answer:

We have a prism with a volume of 16y⁴ + 16y³ + 48y² cubic units.

Its volume is equal to the area of its base times its height.

Of course, for those to be the base area and height of this prism, they would have to multiply to 16y⁴ + 16y³ + 48y² cubic units.

Let's test each of these answers to see which gives us the correct volume.

--------------------------------------------------------------------------------------------------

a base area of 4y square units and height of 4y² + 4y + 12 units

We find the volume by multiplying the base area by the height...

4y(4y² + 4y + 12)

Distribute the 4y to each term inside the parentheses.

16y³ + 16y² + 48y

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 8y² square units and height of y² + 2y + 4 units

We find the volume by multiplying the base area by the height...

8y²(y² + 2y + 4)

Distribute the 8y² to each term inside the parentheses.

8y⁴ + 16y³ + 32y²

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 12y square units and height of 4y² + 4y + 36 units

We find the volume by multiplying the base area by the height...

12y(4y² + 4y + 36)

Distribute the 12y to each term inside the parentheses.

48y³ + 48y² + 432y

This is not the right volume, so these can not be dimensions of our prism.

--------------------------------------------------------------------------------------------------

a base area of 16y² square units and height of y² + y + 3 units

We find the volume by multiplying the base area by the height...

16y²(y² + y + 3)

Distribute the 16y² to each term inside the parentheses.

16y⁴ + 16y³ + 48y²

The volume fits, so these could be the base area and height of our prism.

--------------------------------------------------------------------------------------------------

D. a base area of 16y² square units and height of y² + y + 3 units

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Step-by-step explanation:

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Third option, decreasing
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