Question

Two buses depart two cities moving in the same direction. The speed of the first bus is 54 mph which is 60% of the speed of the second bus. The faster bus caught up to the other bus one hour and thirty minutes after the departure. What is the distance between the buses 24 minutes after the departure.

Answer 1

Answer: Distance between the buses 24 minutes after the departure is given by $36-21.6=14.4\ miles$

Step-by-step explanation:

Since we have given that

Speed of first bus = 54 mph

Speed of second bus is given by

$54=60\%\times \text{Speed of second bus}\\\\\dfrac{54}{0.6}=\text{Speed of second bus}\\\\90\ mph=\text{Speed of second bus}$

Distance covered in 24 minutes by the first train is given by

$54\times \dfrac{24}{60}\\\\=21.6\ miles$

Distance covered in 24 minutes by the second train is given by

$90\times \dfrac{24}{60}\\\\=36\ miles$

Hence, Distance between the buses 24 minutes after the departure is given by $36-21.6=14.4\ miles$