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3 years ago

15

Suppose the required reserve ratio is 20 percent. If banks are conservative and choose not to loan all their excess reserves, th

e real-world deposit multiplier is A) less than 5.B) equal to 5.C) greater than 5.D) equal to 20.

1 answer:

maria [59]3 years ago

5 0

Answer:

Option B

Step-by-step explanation:

Given that the required reserve ratio is 20 percent.

Since banks are conservative they choose not to loan all their excess reserves

i.e. only 20% of deposits is kept as reserve and 80% lent.

This 80% will again be deposited in a bank and 80% of 80 i.e.64% would be lent. Thus this will form a geometric progression infinitely as

deposits $= 1+0.8 + 0.8^2 +0.8^3+...$ with common ratio 0.8<1

Hence infinite sum = $\frac{a}{1-r} =\frac{1}{1-0.8} \\=5$

So deposit multiplier is B) equal to 5

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A company is approached by a new warehouse management systems vendor to adopt a new system. The vendor claims that the warehouse

Ludmilka [50]

Answer:

a

The null hypothesis is $H_o : \mu = 180$

The alternative hypothesis is $H_a : \mu < 180$

b

The decision rule is fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 3 \ minutes = 180 \ seconds$

The sample size is n = 25

The excel sheet is show on the first uploaded image

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu = 180$

The alternative hypothesis is $H_a : \mu < 180$

Generally the sample mean is mathematically represented as

$\= x = \frac{156 + 136 + \cdots + 181}{25}$

=> $\= x = 173.2$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{\frac{\sum (x_i - \= x )^2 }{n} }$

=> $\sigma = \sqrt{\frac{ (156 - 173.2 )^2 + (136 - 173.2 )^2 + \cdots + (181- 173.2 )^2 }{25} }$

=> $\sigma = 24.261$

Generally the test statistics is mathematically represented as

$t = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} } }$

=> $t = \frac{173.2 - 180 }{\frac{24.261}{\sqrt{25} } }$

=> $z = -1.40$

Generally p-value is mathematically represented as

$p-value = P(Z < z)$

=> $p-value = P(Z < -1.40)$

From the z-table

$P(Z < -1.40) = 0.080757$

=> $p-value = 0.080757$

From the obtained value we that $p-value > \alpha$

The decision rule is fail to reject the null hypothesis

The conclusion

There no sufficient evidence to support the vendor claim that the warehouse management system reduces the average pick, pack, and ship time to below 3 minutes(180 seconds) per order through bin location and routing optimization

5 0

3 years ago

Which of these points, if any, is the midpoint of FJ?

ivanzaharov [21]

The mid-point of FJ is the number right in the middle of FJ. Find the mean of F & J. Add regardless of sign

4 + 6 = 10

10/2 = 5

Add 5 to -4

5 + -4 = 1

H is your midpoint

True. As long as AB and BC are on the same line, AB + BC = AC

hope this helps

4 0

3 years ago

in a class of 32 students the mean height of the 14 boys is 1.56 meters and the mean height of all 32 students is 1.151 meters.

Nimfa-mama [501]

Answer: Hence, Mean height of the girls is: 1.48

Step-by-step explanation: It is given that:

in a class of 32 students .

the mean height of 14 boys is 1.56 and the mean height of all 32 students is 1.515.

Since there are 14 boys in a class.

So, number of girls is equal to (32-14)=18.

The mean height of 14 boys is 1.56.

Hence the sum of height of 14 boys is= 1.56×14=21.84

Similarly mean height of 32 students is 1.515.

Hence, sum of height of 32 students=1.515×32=48.48.

Let x denote the mean height of 18 girls.

Hence, sum of height of 18 girls is: 18 x.

Now,

18x+21.84=48.48

( since sum of height of girls and boys is equal to the sum of height of all the students)

so, 18x=48.48-21.84

18 x=26.64

Hence, x=1.48

Hence, Mean height of the girls is: 1.48

4 0

3 years ago

Nancy’s morning routine involves getting dressed, eating breakfast, making her bed, and driving to work. Nancy spends ⅓ of the t

Lina20 [59]

26 minutes to get to work

5 0

2 years ago

Rafael wants to earn at least $45 trimming trees. He charges $8 per hour and pays $3 in equipment fees. What are the possible nu

pshichka [43]

Answer:

6 $\leq$ r

Step-by-step explanation:

45 $\leq$ 8r-3

48 $\leq$ 8r

6 $\leq$ r

8 0

3 years ago