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Alecsey [184]
3 years ago
13

30men can finish 1/7of a work in 2days.18men will do othe remaining work in ?

Mathematics
1 answer:
Dovator [93]3 years ago
7 0
7/7-1/7=6/7 is the rest of work
1/7 work takes 2days
6*1/7=6/7 work takes 6*2days=12days
30 men takes 12 days to finish the rest of work (6/7)
18 men takes 18*12/30= 7.2days
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Answer:

We need to develop a one-tail t-student test ( test to the right )

We reject H₀  we find evidence that student spent more than 24,5 hours on the phone

Step-by-step explanation:

Sample size  n = 15     n < 30

And we were asked if the mean is higher than, therefore is a one-tail t-student test ( test to the right )

Population mean   μ₀  = 24,5

Sample mean   μ  =  25,7

Sample standard deviation s = 2

Hypothesis Test:

Null Hypothesis      H₀                             μ  =  μ₀

Alternative Hypothesis     Hₐ                  μ  >  μ₀

t (c) =  ?

We will define CI = 95 %  then   α = 5 %   α = 0,05    α/2 =  0,025

n = 15     then degree of freedom    df = 14

From t-student table  we get:  t(c) = 2,1448

And  t(s)

t(s) = ( μ  -  μ₀  ) / s/√n

t(s) = (25,7 - 24,5) /2/√15

t(s) = 2,3237

Now we compare   t(c)   and  t(s)

t(c)  =  2,1448         t(s)  = 2,3237

t(s) > t(c)

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GuDViN [60]

Answer:

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Step-by-step explanation:

The n th term of an arithmetic sequence is

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a_{25} = 12 + (24 × 4) = 12 + 96 = 108

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