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Nataly_w [17]
3 years ago
11

2/3,2/8,2/6 list from greatest to least

Mathematics
1 answer:
NISA [10]3 years ago
7 0
2/8, 2/3, 2/6 hope this helps lol
You might be interested in
What two numbers adds up 2 and multiplies -80
viva [34]
-8 and 10. 

The 8 has to be negative because otherwise the 2 would end up being negative, not positive.
7 0
3 years ago
The average cost of living for a family of four in twelve different cities was found to be $65,351 with a standard deviation of
Andrej [43]

Answer:

$65,351+/-$3,661.73

= ( $61,689.27, $69,012.73)

Therefore, the 90% confidence interval (a,b) = ( $61,689.27, $69,012.73)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = $65,351

Standard deviation r = $7,711

Number of samples n = 12

Confidence interval = 90%

z(at 90% confidence) = 1.645

Substituting the values we have;

$65,351+/-1.645($7,711/√12)

$65,351+/-1.645($2,225.973962860)

$65,351+/-$3661.727168905

$65,351+/-$3,661.73

= ( $61,689.27, $69,012.73)

Therefore, the 90% confidence interval (a,b) = ( $61,689.27, $69,012.73)

6 0
3 years ago
Charlie bought 2 3/4 pounds of pears for $.76 per pound and 2 3/4 pounds of grapes for $1.40 per pound how much money in dollars
Darina [25.2K]

Answer:

$5.94

Step-by-step explanation:

Multiply 2.75 by $0.76 to get $2.09

Multiply 2.75 by $1.40 to get $3.85

Add $3.85 and $2.09 to get $5.94

3 0
2 years ago
Calibrating a scale:
lana66690 [7]

Answer:

We conclude that the calibration point is set too high.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =  1000 grams

Sample mean, \bar{x} =  1001.1 grams

Sample size, n = 50

Alpha, α = 0.05

Population standard deviation, σ = 2.8 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 1000\text{ grams}\\H_A: \mu > 1000\text{ grams}

We use One-tailed(right) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{ 1001.1 - 1000}{\frac{2.8}{\sqrt{50}} } = 2.778

Now, z_{critical} \text{ at 0.01 level of significance } = 2.326

Since,  

z_{stat} > z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. We accept the alternate hypothesis. We conclude that the calibration point is set too high.

6 0
3 years ago
PLEASE HELP ME! I NEED THIS BY TODAY
mrs_skeptik [129]

Answer: this is a INVERSE choice C

5 0
2 years ago
Read 2 more answers
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