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3 years ago

13

Geometry

1 answer:

SSSSS [86.1K]3 years ago

7 0

Sorry man, don’t know it, hopefully you get someone who knows

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Please answer this correctly

elena-s [515]

Answer:

30

Step-by-step explanation:

If these two shapes are similar, then ratios of corresponding sides will stay constant. Therefore:

$\dfrac{g}{45}=\dfrac{50}{75}$

Multiply both sides by 45:

$g=\dfrac{50\cdot 45}{75}=30$

Hope this helps!

8 0

2 years ago

What is the formula for Inflation Rate?

snow_lady [41]

Inflation Rate= CPI2-CPI1/CP1 x 100

3 0

3 years ago

Salvador inherited $20,000 and he plans to invest into a savings account that earns 6% interest compounded annually. Assuming he

Scilla [17]

It’s 15,816.95. That the answer

4 0

2 years ago

In Sarah‘s dance class 1/16 of the girls are also on the soccer team. what is the decimal form of this fraction

Alenkasestr [34]

Answer:0.0625

Step-by-step explanation:

5 0

3 years ago

A submarine left Diego Garcia five hours before a cruise ship. The ships traveled in opposite directions. The cruise ship travel

Rina8888 [55]

Answer:

The speed of the submarine is 15.429 miles per hour.

Step-by-step explanation:

Let suppose that both ships travel at constant velocities. As we know that both travel in opposite directions, it is supposed that cruise ship moves in +x direction, whereas submarine in -x direction. Kinematic equations for each sheep are described below:

Ship

$x_{Sh} = x_{o} + v_{Sh}\cdot t$

Submarine

$x_{Su} = x_{o}+v_{Su}\cdot t$

Where:

$x_{o}$ - Position of Diego Garcia island, measured in miles.

$x_{Sh}$ , $x_{Su}$ - Current positions of ship and submarine, measured in miles.

$v_{Sh}$ , $v_{Su}$ - Velocities of ship and submarine, measured in miles per hour.

$t$ - TIme, measured in hours.

If we know that $x_{Sh} - x_{Su} = 241\,mi$ , $v_{Sh} = 19\,\frac{mi}{h}$ and $t = 7\,h$ , then:

$x_{Sh} - x_{Su} = (v_{Sh}-v_{Su})\cdot t$

We clear now the velocity of submarine:

$\frac{x_{Sh}-x_{Su}}{t} = v_{Sh}-v_{Su}$

$v_{Su} = v_{Sh}-\frac{x_{Sh}-x_{Su}}{t}$

$v_{Su} = 19\,\frac{mi}{h} -\frac{241\,mi}{7\,h}$

$v_{Su} = -15.429\,\frac{mi}{h}$

Speed of the submarine is the magnitude of its velocity, which is 15.429 miles per hour.

4 0

2 years ago