3 years ago

Geometry

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

7 0

Sorry man, don’t know it, hopefully you get someone who knows

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Answer:

Possible error in the volume of the cylinder is ±8π inch³.

Step-by-step explanation:

We have, a right circular cylinder with radius, r = 4 inches and height, h = 10 inches.

As, the volume of a cylinder = $\pi r^{2} h$

So, volume of the given cylinder, V = $10\pi r^{2}$

Then, $\frac{dV}{dr}=20\pi r$ i.e. $dV=(20\pi r)dr$ ,

where dV and dr represents the possible change (or error) in volume and radius of the cylinder respectively.

As, we have,

r = 4 inches and dr = ±0.1 inch.

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