Answer:
A, C & D
Step-by-step explanation:
A) 1 + 3x = -x + 4 {subtract 1}
1 + 3x -1 = -x + 4 - 1
3x = -x + 3 {add x}
3x + x = -x + 3 + x
4x = 3 {Divide by 4}
4x/x = 3/4
x = 3/4
C) 1 + 3x = -x +4 {Add x}
1+ 3x + x = - x +4 + x
1 + 4x = 4 {subtract 1}
4x = 4 - 1
4x = 3 {Divide by 4}
D) 1 + 3x = -x + 4 { Subtract 3x}
1 = -x + 4 -3x
1 = -4x + 4 Subtract 4}
1 - 4 = -4x
-3 = -4x {Divide by -4}
-3/-4 = x
x = 3/4
x = 3/4
Ya I believe that is the answer. I got the exact same thing.
Hey Jinx :)
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Note that a decay has a rate between 0 and 1, and a growth as a rate of 1 or higher.
y = 1/2(1 + 0.03)^t → y = 1/2(1.03)^t (Rate is more then 0) GROWTH
y = 0.3(0.95)^t → (Rate is between 0 and 1) DECAY
y = ((1+0.03)^1/2)^2t → y = y = 1.014^2t (Rate is more then 0) GROWTH
y = 200(0.73)^t → (Rate is between 0 and 1) DECAY
y = 4(1/4)^t → (Rate is between 0 and 1) DECAY
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Hope This Helped! Good Luck!
Answer:
4
Step-by-step explanation:
These are the same line when you graph. So there are infinite solutions to this system.
