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kirill [66]
3 years ago
13

I need help with this as fast as possible, I have no idea what it could be-

Mathematics
1 answer:
sergejj [24]3 years ago
3 0
Can’t see the pic .........................
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What's the square root of 628
Galina-37 [17]
4rt33 or 4 times the square root of 33
4 = the square root of sixteen, so the square root of 16 times the square root of 33 = the square root of 628
8 0
3 years ago
PLEASE HELP ME IM STRUGGLING!!!
Kitty [74]

Answer:

The required answer is c=7\sqrt{3}

Therefore the number in green box should be 7.

Step-by-step explanation:

Given:

AB = 7√2

AD = a , BD = b , DC = c , AC = d

∠B = 45°, ∠C = 30°

To Find:

c = ?

Solution:

In Right Angle Triangle ABD Sine identity we have

\sin B = \dfrac{\textrm{side opposite to angle B}}{Hypotenuse}\\

Substituting the values we get

\sin 45 = \dfrac{AD}{AB}= \dfrac{a}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}= \dfrac{a}{7\sqrt{2}}\\\\\therefore a=7

Now in Triangle ADC Tangent identity we have

\tan C = \dfrac{\textrm{side opposite to angle C}}{\textrm{side adjacent to angle C}}

Substituting the values we get

\tan 30 = \dfrac{AD}{DC}= \dfrac{a}{c}\\\\\dfrac{1}{\sqrt{3}}=\dfrac{7}{c}\\\\\therefore c=7\sqrt{3}

The required answer is c=7\sqrt{3}

8 0
3 years ago
in the blanks below. Find the slope of the line passing through the points (-9, 2) and (9,2). slope: ​
user100 [1]

I will assume that we are trying to find the slope between (-9,2) and (9, 2)

The slope's equation ⇒  \frac{y2-y1}{x2-x1}

<u>Let's set the variables</u>:

   (x1, y1) --> (-9, 2)

   (x2, y2) --> (9, 2)

<u>Now let's plug them in:</u>

  Slope = \frac{2-2}{9--9} =\frac{0}{18} =0

<u>Thus the slope of the line is 0.</u>

Hope that helps!

3 0
2 years ago
3x +15= 2x + 10 + x +5 how many solutions​
Travka [436]

3x +15= 2x + 10 + x +5\\\\3x-2x-x=  10  +5-15\\\\0=0

infinitely many solutions

6 0
3 years ago
If the discriminant of a quadratic equation is positive, which of the following is true of the equation?
Yanka [14]
For this case suppose that we have a quadratic equation of the form:
 ax ^ 2 + bx + c&#10;
 The solution to the quadratic recuacion is given by:
 x =  \frac{-b +/-  \sqrt{b^2 - 4ac}}{2a}
 Where,
 The discriminant is:
 b ^ 2 - 4ac&#10;
 When the discriminant is greater than zero, then the root is positive, and therefore, we have two positive real solutions.
 Answer:
 
B. it has two real solutions
3 0
3 years ago
Read 2 more answers
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